Answer this question thanks
1 answer:
First divide 6 to both sides to isolate q. Since 6 is being multiplied by q, division (the opposite of multiplication) will cancel 6 out (in this case it will make 6 one) from the right side and bring it over to the left side.
18 ≥ 6q
18 ÷ 6 ≥ 6q ÷ 6
3 ≥ 1q
3 ≥ q
For the graph will you have a empty or colored in circle?
If the symbol is ≥ or ≤ then the circle will be colored in. This represents that the number the circle is on is included.
If the symbol is > or < then the circle will be empty. This represents that the number the circle is on is NOT included.
Which direction will the ray go?
If the variable is LESS then the number then the arrow will go to the left of the circle.
If the variable is MORE then the number then the arrow will go to the right of the circle.
In this case your inequality is:
3 ≥ q OR q ≤ 3
aka 3 is greater then q OR q is less then 3
This means that the graph will have an colored circle and the arrow will go to the left of 3. Look at image below.
Hope this helped!
~Just a girl in love with Shawn Mendes
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Answer:
(a) The probability that at least one of these components will need repair within 1 year is 0.0278.
(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.
Step-by-step explanation:
Denote the events as follows:
<em>A</em> = video components need repair within 1 year
<em>B</em> = electronic components need repair within 1 year
<em>C</em> = audio components need repair within 1 year
The information provided is:
P (A) = 0.02
P (B) = 0.007
P (C) = 0.001
The events <em>A</em>, <em>B</em> and <em>C</em> are independent.
(a)
Compute the probability that at least one of these components will need repair within 1 year as follows:
P (At least 1 component needs repair)
= 1 - P (No component needs repair)
Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.
(b)
Compute the probability that exactly one of these component will need repair within 1 year as follows:
P (Exactly 1 component needs repair)
= P (A or B or C)
Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.