A bicycle pedal is pushed straight downwards by a foot with a 11 Newton force. The shaft of the pedal is 20 cm long. If the shaf
t is π/6 radians past horizontal, what is the magnitude of the torque about the point where the shaft is attached to the bicycle?
1 answer:
Answer: 1.1 Nm
Step-by-step explanation:
The formula for torque is T = r · F · sin θ
where θ = π/6, r = 20 cm = 0.2 m, F = 11 N
formula for converting radians to degrees is 1 rad × 180/π = 57.296°
θ = π/6 · 180/π = 30°
Substituting r into the formula for torque, we have
T = 0.2 x 11 x sin 30° = 0.2 x 11 x 0.5
T = 1.1 Nm
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