<span>f(x<0)=-f(x>0)=-x^2+5x+12
When x>0, x^2-5x-12=12, x=8, y=12
Therefore, f(x)=12 goes through point (8,12).</span>
Hey there! I'm happy to help!
When rotating a point 90 degrees clockwise about the origin, our original point (x,y) becomes (-y,x), because it is now at a negative y-value.
We see that our point P is at (1,2). We can use this rotation formula to find the coordinates of P' (the new spot where P is)/
(x,y)⇒(-y,x)
(1,2)⇒(-2,1)
Therefore, the coordinates of the point P' are (-2,1).
Have a wonderful day! :D
Answer:x
x
=
−
32
/7
Step-by-step explanation:
