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Masja [62]
4 years ago
9

One tenth of 3000 is 10 times as much as?

Mathematics
2 answers:
loris [4]4 years ago
5 0

Answer:

Therefore, one tenth of 3000 is 10 times as of 30.

Step-by-step explanation:

Given  : 3000

To find : one tenth of 3000 is 10 times as much as.

Solution : We have given  3000

According to question

one tenth of 3000

\frac{1}{10}* 3000 =300.

So, We can write 300 as 10 * 30

We can say 300 is 10 times of 30.

\frac{1}{10}* 3000 =30 * 10

Hence one tenth of 3000 is 10 times as of 30.

Therefore, one tenth of 3000 is 10 times as of 30.

Nostrana [21]4 years ago
3 0
The answer is 300 is 10 times as much as 3000
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Consider the number of the adult tickets is x
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3 years ago
2.16 (the 6 is repeating) as a fraction (no improper fractions)
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Answer:

2 4/25

Step-by-step explanation:

First, I made the decimal into 2 16/100. Then, keep simplifying the 16/100 until it is fully simplified.

6 0
3 years ago
at an amusement park there are 5150 moon shoes and 3041 cactus plants there are a total of 10881 prizes how many hats are at the
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3 years ago
If a factory continuously dumps pollutants into a river at the rate of the quotient of the square root of t and 45 tons per day,
julsineya [31]
<h2>Hello!</h2>

The answer is:

The first option, the amount dumped after 5 days is 0.166 tons.

<h2>Why?</h2>

To solve the problem, we need to integrate the given expression and evaluate using the given time.

So, integrating we have:

\int\limits^5_0 {\frac{\sqrt{t} }{45} } \, dt=\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \, dt\\\\\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \ dt=\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt\\\\\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt=(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)\\\\(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)=(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)

(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)=(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)\\\\(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)=(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)\\\\(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)=(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})\\\\(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})=\frac{2}{135}*11.18-0=0.1656=0.166

Hence, we have that the amount dumped after 5 days is 0.166 tons.

Have a nice day!

5 0
4 years ago
Find the coordinates of the intersection of the diagonals of parallelogram qrst with vertices q(-8,1), r(2,1), s(4,-3), t(-6,-3)
TiliK225 [7]

Answer:

Point of intersection is (-2, -1).

Step-by-step explanation:

The diagonals bisect each other so we only need to find the midpoint  of one of the diagonals. We'll use the diagonal qs:-

Midpoint = (-8 + 4)/2, (1 + -3)/2

= (-2, -1)


3 0
4 years ago
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