Question

For what values of t, if any, is given vector parallel to vector u = (4,-1): (8t, 2t)? and (1,t^2)?

Answer 1

The vector would have to be a scalar of (4,-1) in order to be parallel to it
so
 4 = 8t   -1 = 2t

t= 4/8 = 1/2
-1=2t
t= -1/2