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bekas [8.4K]
4 years ago
6

For what values of t, if any, is given vector parallel to vector u = (4,-1): (8t, 2t)? and (1,t^2)?

Mathematics
1 answer:
Radda [10]4 years ago
3 0
The vector would have to be a scalar of (4,-1) in order to be parallel to it
so
 4 = 8t   -1 = 2t

t= 4/8 = 1/2
-1=2t
t= -1/2
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