Question

Please help me with thus

Answer 1

The answer for this question would be C. This statement supports his answer because a solution is not possible when the denominator of a fraction is equal to zero, making it undefined. This is shown when -1/2 is plugged into 6x+3, the denominator of the equation, and it results in the answer 0.

Answer 2

$- 2 \: = \: \frac{2x \: + \: 1}{6x \: + \: 3}$
Multiplying and Dividing R.H.S. by 3, we get,
$- 2 \: = \: \frac{1}{3} \: \times \: \frac{6x \: + \: 3}{6x \: + \: 3}$
or,
$- 2 \: = \: \frac{1}{3}$
Which is not possible, so, no such equation can exist.
Hence, the answer is (C) as the denominator becomes 0, which doesn't make sense, as it is an Indeterminate form.