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umka21 [38]
3 years ago
8

Given the area of circular base and the area of curved surface of the cone are 98.56 cm² and 264 cm² respectively. Find the heig

ht of the cone, in cm.​
Mathematics
1 answer:
____ [38]3 years ago
5 0

Answer: height = 13.9 cm

Step-by-step explanation:

The base area of a cone is the area of a circle. Given that base area = 98.56 cm^2

Base area = πr^2

Substitutes the value into the formula

98.56 = 22/7 × r^2

Cross multiply

689.92 = 22r^2

r^2 = 689.92/22

r = sqrt ( 31.36 )

r = 5.6 cm

Also, the curved surface area of a cone is πrL

Where the given value is 264 cm^2

Substitutes the value into the formula

264 = 22/7 × 5.6 × L

Where L = slant height

Cross multiply

123.2L = 1848

L = 1848 /123.2

L = 15 cm.

Using pythagorean theorem to find the height H of the cone.

H^2 = L^2 - r^2

H^2 = 15^2 - 5.6^2

H = sqrt( 193.64 )

H = 13.9 cm

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Answer:

the 95% confidence interval to estimate the population mean is between  1.62 and 6.50

Step-by-step explanation:

given data

distribution = 4.5, 6.4, 2.3, 1.8, 5.3

so n = 5

confidence interval = 95%

to find out

the population mean is between

solution

first we calculate the mean i.e.

mean =  \frac{1}{n}\sum_{i=1}^{n}x(i)

mean =  4.5+ 6.4+ 2.3+ 1.8+ 5.3 / 5

mean = 4.06

now we calculate the standard deviation i.e.

standard deviation =   \sqrt{\frac{1}{n-1}\sum (x(i)-mean)^2}

standard deviation =   \sqrt{\frac{1}{5-1}\sum (x(i)-mean)^2}

standard deviation =   \sqrt{\frac{1}{5-1} (4.5-5)^2+(6.4-5)^2 +(2.3-5)^2+(1.8-5)^2+(5.3-5)^2}

standard deviation =   \sqrt{\frac{1}{4} (4.5-5)^2+(6.4-5)^2 +(2.3-5)^2+(1.8-5)^2+(5.3-5)^2}

standard deviation =  2.226544

so 95 % confidence interval is i.e. mean +/- t(5) * standard deviation/ \sqrt{n}

here t(5) will be 2.45

so

95 % confidence interval=  4.06 +/- 2.45 * 2.226 / \sqrt{5}

95 % confidence interval= 1.62 and 6.50

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