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2 years ago

What is 67 divided by 19

Mathematics

2 answers:

xeze [42]2 years ago

7 0

67 divided by 19 equal 3.52631578947
hope this help

Shkiper50 [21]2 years ago

6 0

3.52 hope it helpss...

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There are 235 whistles and 42 bells in the store. Ryan counts 128 whistles on the shelf. How many whistles are not on the shelf

yanalaym [24]

There would be 107 whistles
-equation- 235-128=107

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2 years ago

What is the solution of two thirds x=12

joja [24]

Hi there!

To solve this problem, we need to simplify.

2/3x = 12

To isolate x, we should multiply both sides of the equation by the reciprocal of 2/3 to make x equal to a value:

Reciprocal of 2/3 = 3/2

x = 12 * 3/2
x = 18

Hope this helps!

8 0

2 years ago

Given the diagram below, what statement can you not make?

Vaselesa [24]

Answer:

b, 5=3

Step-by-step explanation:

4 0

2 years ago

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Use series to verify that <img src="https://tex.z-dn.net/?f=y%3De%5E%7Bx%7D" id="TexFormula1" title="y=e^{x}" alt="y=e^{

SVETLANKA909090 [29]

$y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\$

$\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\$

This shows that $y' = y$ is true when $y = e^x$

-----------------------

Note 1: A more general solution is $y = Ce^x$ for some constant C.
Note 2: It might be tempting to say the general solution is $y = e^x+C$ , but that is not the case because $y = e^x+C \to y' = e^x+0 = e^x$ and we can see that $y' = y$ would only be true for C = 0, so that is why $y = e^x+C$ does not work.

6 0

2 years ago

Solve for y: 2y + 3 =11 Solve for x: 2/3x = 18

laiz [17]

Answer: y=4 x=27

Step-by-step explanation: 2y+3=11

-3 -3

2y=8

/2 /2

y=4

2/3x=18

(3) (3)

2x=54

/2 /2

X=27

5 0

2 years ago

Read 2 more answers