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Igoryamba
3 years ago
12

I have k quarters, five less quarters than nickels and one more than twice as many dimes as quarters. Find the value of the coin

s in cents in terms of k.
Mathematics
2 answers:
Alenkinab [10]3 years ago
5 0

Answer:

(35k + 20) cents

Step-by-step explanation:

First of all, let us have the value of each unit:

1 quarter = 25 cents

1 nickel = 5 cents

1 dime = 10 cents

Given that number of quarter = k

Quarters are 5 lesser than Nickels, so number of nickels = k+5

One more than twice as many dimes as quarters:

k = 2 \times Number of Dimes + 1

So, number of dimes = \frac{1}{2}(k-1)

Value of quarters = 25 \times k cents

Value of nickels = 5 \times (k+5) = (5k+25)\ cents

Value of dimes = \frac{1}{2}(k-1) \times 10 = (5k-5)\ cents

So, total value of coins =

25k + 5k +25 +5k-5\\\Rightarrow (35k+20)\ cents

Lady_Fox [76]3 years ago
3 0

Answer:

35k+20

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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