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3 years ago

I NEED HELP PLEASE, THANKS! :)

Mathematics

1 answer:

brilliants [131]3 years ago

8 0

Answer:

320 square units

Step-by-step explanation:

The four rectangles that approximate the area are shown in the graph. They have heights of 48, 64, 48, and 0. The width of each is 2. Then the total area is the sum of the products of length and width:

2·48 +2·64 +2·48 +2·0 = 2·160 = 320 . . . square units

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Zach is 4 years older than twice his sister Maya’s age. Maya is 5 years old. How old is Zach? Enter your answer in the box.

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4 years ago

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Out of these lines which are parallel?Lines: j- y= 2/3x+1/2, k- y=1/2x+2/3, l- y=2/3x+3/2, m-y=3/2x+1/2

Crazy boy [7]

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Step-by-step explanation:

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3 years ago

19 POINTS HELP PLEASE! Complete the table and pattern. Determine the common difference. Write the explicit rule.

Sonbull [250]

$a_1=-20,\ a_3=-15\\\\2d=a_3-a_1\to 2d=-15-(-20)\to2d=-15+20\to2d=5\to d=2.5\\\\a_n=a_1+(n-1)d\to a_n=-20+(n-1)(2.5)=-20+2.5n-2.5=2.5n-22.5\\\\a_2=2.5(2)-22.5=5-22.5=-17.5\\\\a_4=2.5(4)-22.5=10-22.5=-12.5\\\\a_6=2.5(6)-22.5=15-22.5=-7.5$

f(n)| -20 | -17.5 | -15 |-12.5| -10 | -7.5 |

First term: -20 Common Difference: 2.5

Explicit Rule: $a_n=2.5n-22.5$ Recursive Rule: $a_1=-20,\ a_n=a_{n-1}+2.5$

$a_1=123,\ a_2=131\\\\d=a_2-a_1\to d=131-123=8\\\\a_n=a_1+(n-1)d\to a_n=123+(n-1)(8)=123+8n-8=8n+115\\\\a_3=8(3)+115=24+115=139\\\\a_5=8(5)+115=40+115=155\\\\a_6=8(6)+115=48+115=163$

f(n)| 123 | 131 | 139 | 147 | 155 | 163 |

First term: 123 Common Difference: 8

Explicit Rule: $a_n=8n+115$ Recursive Rule: $a_1=20,\ a_n=a_{n-1}+8$

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3 years ago

Is .5 a non integer between o and 1

Elodia [21]

0 and 1 are integers, there are no other integers between them

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3 years ago

function travelSpeed = CalculateTravelSpeed(startX, startY, endX, endY, travelTime) % startX, startY: Starting coordinates % end

Ilia_Sergeevich [38]

Answer:

The functions in Python is as follows:

from math import *

def CalculateTravelSpeed(startX,startY,endX,endY,travelTime):

travelSpeed = EuclideanDist(startX, startY, endX, endY) / travelTime

return travelSpeed

def EuclideanDist(startX, startY, endX, endY):

dist = sqrt((startX - endX)**2 + (startY - endY)**2)

return dist

Step-by-step explanation:

from math import *

This defines the CalculateTravelSpeed function

def CalculateTravelSpeed(startX,startY,endX,endY,travelTime):

This calls the EuclideanDist function to calculate the distance; Next, the speed is calculated

travelSpeed = EuclideanDist(startX, startY, endX, endY) / travelTime

This returns the calculated speed

return travelSpeed

This defines the EuclideanDist function

def EuclideanDist(startX, startY, endX, endY):

This calculates the distance from the given coordinates

dist = sqrt((startX - endX)**2 + (startY - endY)**2)

This returns the calculated distance

return dist

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3 years ago