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Anestetic [448]
3 years ago
10

Please help! Picture included!!!

Mathematics
2 answers:
RideAnS [48]3 years ago
7 0
Answer is 18,
24/8 = 3
So
6x 3 = 18
V125BC [204]3 years ago
5 0
The answer is c)32 hope this helps



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Les tried to evaluate 600 x 4 step by step.
mestny [16]
The answer is step 1 because it should have been 600 x 4= 100 x 6 x 4.
8 0
2 years ago
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Can someone please answer. There is one problem. There's a picture. Thank you!
Mnenie [13.5K]
Use the Sine Law: \frac{sin(A)}{a} = \frac{sin(B)}{b} = \frac{sin(C)}{c}

In this case:
\frac{sin(44)}{17}=\frac{sin(60)}{e}
therefore:
e=17\frac{sin(60)}{sin(44)} \approx 21.2
6 0
3 years ago
The vertical height v, in feet, of a snowboarder jumping off of an overhang can be modeled by the function h(t)=15-10t-16t^2, wh
olga55 [171]
I don't know for sure, but I think there might be an error in the way you copied your function. In all of my dealings with these types of problems, I have learned the formula to be h(t) = 15 + 10t - 16t^2. Notice the plus in front of the "10t". This is due to the fact that if he pushes off of the overhang he would have an upward force of 10 feet per second as soon as his feet left the ground. The only thing pulling him back to Earth is gravity, modeled by the "-16t^2". This is derived from a bit of slightly advanced physics involving the gravitational constant, but let's work under my formula for a second...

Either way, we will wind up using the Quadratic Formula (or possibly factoring if the numbers are easy enough to work with). So let's start. 

h(t)= 15 +10t - 16t^2

In order to use the QF or factoring I will need to make h(t)=0. Simply done by:

0= 15 +10t -16t^2

Looking at the numbers, I'd prefer to use the QF so here it is:

x= \frac{-b + or -  \sqrt{b^{2}-4ac } }{2a}

I know that my answer will need to be positive since you can't have a negative value when dealing with time, so I will eliminate the positive sign from the "+or-" part leaving me with:

x= \frac{-b -\sqrt{b^{2}-4ac } }{2a}

And I know that a= -16, b= 10, and c=15. So all that's left to do is substitute and solve.

x= \frac{-10 -\sqrt{-16^{2}-4*-16*15 } }{2*-16} 

There's a decent amount of math that would be difficult and sloppy for me to do over the computer, but all you need to do is solve the rest of the equation and you would get your answer.

Exact answer: \frac{5-4 \sqrt{15} }{8} or rounded answer: ≈1.31 seconds.

Hope this helps!
NoThisIsPatrick

7 0
3 years ago
Read 2 more answers
Which expression is equivalent to (5g^4+5g^3-17g^2+6g)-(3g^4+6g^3-7g^2-12)/g+2
ankoles [38]

Option C:

2 g^{3}-5 g^{2}+6

Solution:

Given expression:

$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}

To find which expression is equal to the given expression.

$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}

Expand the term -\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right):-3 g^{4}-6 g^{3}+7 g^{2}+12

         $=\frac{5 g^{4}+5 g^{3}-17 g^{2}+6 g- 3 g^{4}-6 g^{3}+7 g^{2}+12}{g+2}

Arrange the like terms together.

         $=\frac{5 g^{4}- 3 g^{4}+5 g^{3}-6 g^{3}-17 g^{2}+7 g^{2}+6 g+12}{g+2}

         $=\frac{2 g^{4}- g^{3}-10 g^{2}+6 g+12}{g+2}

Factor the numerator 2 g^{4}-g^{3}-10 g^{2}+6 g+12=(g+2)\left(2 g^{3}-5 g^{2}+6\right)

         $=\frac{(g+2)\left(2 g^{3}-5 g^{2}+6\right)}{g+2}

Cancel the common factor g + 2, we get

         =2 g^{3}-5 g^{2}+6

Hence option C is the correct answer.

8 0
2 years ago
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Which equation has the graph shown below? (0, 3) (2,0) ​
professor190 [17]

Answer:

6x+4y=12

Step-by-step explanation:

when x-intercept is 0

6(0)+4y=12

0+4y=12

divide by 4 both side

y=3

when y-intercept is 0

6x+4(0)=12

6x+0=12

6x=12

divide by 6 both side

x=2

6 0
3 years ago
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