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3 years ago

There is a bag filled with 6 blue and 5 red marbles.

Mathematics

2 answers:

lorasvet [3.4K]3 years ago

7 0

Answer:

It has to be red cause it is

Mkey [24]3 years ago

7 0

Answer:

the probability of the same colour being taken from the bag is a 5:5 ratio if the first marble is not put back

Step-by-step explanation:

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Miguel’s teacher asked him to color 4/8 of his grid. He must use 3 colors: red, blue, and green. There must be more green sectio

wolverine [178]

Color 2/8 of grid in green, 1/8 grid in red and 1/8 grid in blue

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3 years ago

Help - Math Test-need answer immediately I’ll give brainliest.

ludmilkaskok [199]

Answer:

The answer is C the 2 rectangles

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2 years ago

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Need this ASAP Please

Naily [24]

Answer:

To be Honest I kinda do know but I can solve the equation for you if that helps

Step-by-step explanation:

5x+15y-6 is the answer

first you will add all of them and then distribute

Remove parentheses

=3x-18+15y+6+2x+6

Group like terms

=3x+2x+15y-18+6+6

Add similar elements

=5x+15y-18+6+6

Finally Add/Subtract the numbers

=5x+15y-6

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3 years ago

Order these numbers from least to greatest. 1.401, 1.2011, 1.2, 1.41

ira [324]

Answer:

From least to greatest, the correct order is 1.2, 1.2011, 1.401, and 1.41.

Step-by-step explanation:

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3 years ago

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Find gradient xe^y + 4 ln y = x² at (1, 1)

cricket20 [7]

$xe^y+4\ln y=x^2$

Differentiate both sides with respect to x, assuming y = y(x).

$\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}$

$\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x$

$\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

$e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

Solve for dy/dx :

$e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x$

$\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}$

If y ≠ 0, we can write

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}$

At the point (1, 1), the derivative is

$\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}$

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3 years ago