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Natalija [7]
3 years ago
7

What would be the 99th number in the pattern shown below

Mathematics
1 answer:
Oliga [24]3 years ago
8 0
Well.. what is it can you put up a pic of it
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Find the missing dimension:if the perimeter is 6yards and the length is 6ft .what is the width?in yards
larisa [96]
Since you haven't identified this figure, I'm going to assume that it's a rectangle.

The Perimeter of a rectangle of length L and width W is P = 2L + 2W.

Here you are given the Perimeter and the length, and are to find the width, W.

Solving the above equation for W, we get P - 2L = 2W.
Dividing by 2 (to isolate that W), we get 

P
-- - L = W
 2

Substitute P= 6 yds and L = 6 feet (or 2 yds), find W (in yards).
8 0
3 years ago
I’m going to be posting a lot of math questions so look at my account if you wanna answer the rest
IRINA_888 [86]

Answer:

3.Area=πr²

d=14ft

r=7 ft

22/7*7*7

area=154ft²

5.area =1/2 bh

h=13cm

area=32.5cm²

32.5=1/2*13*b

32.5=13/2b

=5.0 or 5

base=5cm

Step-by-step explanation:

4 0
2 years ago
A fruit juice box contains 6% juice. How is this percent written as a decimal?
asambeis [7]
The answer would be 0.06 or just .06
3 0
3 years ago
What is the value of the expression when a = 6, b = 4,and c = 8? 2a/3b-c A.1 B. 3 C.8 D.12
scoray [572]
2(6)/3(4)-8
12/12-8
12/4=3
B. 3 is the answer, hope this helps!
6 0
3 years ago
. Leslie is blowing up one of her favorite photographs to hang on her wall. If the photo's original length and height were 8 inc
Katena32 [7]

Answer:

L_2 = 2\frac{2}{15}\ ft

Step-by-step explanation:

Given

Original

Length(L_1) = 8\ in

Height (H_1) = 15\ in

New

Height (H_2) = 4\ ft

Required

Determine the new length (L2)

Since the original photographs was blown up; the original and the new photographs would have the same ratio

i.e.

Ratio = L_1 : H_1

and

Ratio = L_2 : H_2

Equate both ratios

L_1 : H_1 = L_2 : H_2

Rewrite as fraction

\frac{L_1}{H_1} = \frac{L_2}{H_2}

Substitute values for L1, H1 and H2

\frac{8}{15} = \frac{L_2}{4}

Multiply both sides by 4

4 * \frac{8}{15} = \frac{L_2}{4} * 4

4 * \frac{8}{15} = L_2

\frac{4 * 8}{15} = L_2

\frac{32}{15} = L_2

2\frac{2}{15} = L_2

L_2 = 2\frac{2}{15}\ ft

The new length must be 2\frac{2}{15}\ ft

7 0
3 years ago
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