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3 years ago

14

What is the initial value of the function represented by the graph?

1 answer:

ASHA 777 [7]3 years ago

4 0

<span>In the question "What is the initial value of the function represented by the graph?" The initial value of a function is the value of the function when x = 0, i.e. f(0). For the graphof a function, the initial value is the point where the graph crosses the y-axis. For the given graph, the graph crossed the y-axis at the point (0, 4). Therefore, the initial value of the function represented by the graph is 4.</span>

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Find the number that we can place in the box, so that the resulting quadratic is the square of a binomial.

Arturiano [62]

We need a number to complete

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Since we have

$2xc=\dfrac{4}{5}x \iff 2c=\dfrac{4}{5}\iff c=\dfrac{4}{10}=\dfrac{2}{5}$

And so the expanded square is

$\left( x+\dfrac{2}{5}\right)^2=x^2+\dfrac{4}{5}x+\dfrac{4}{25}$

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4 years ago

On the grid draw the graph of x + 2y =7

Elena-2011 [213]

Answer:

See attachment for graph

Step-by-step explanation:

Given

$x + 2y = 7$

Required

Draw the graph

First, we identify at least 2 possible values of x and y

Let $x = 1$

Solve for y

$x + 2y = 7$

$1 + 2y = 7$

$2y = 6$

$y = 3$

So, a point is: $(1,3)$

Let $x = 3$

Solve for y

$x + 2y = 7$

$3 + 2y = 7$

$2y = 7 -3$

$2y = 4$

$y = 2$

So, another point is: $(3,2)$

<em>Plot </em> $(1,3)$ <em> and </em> $(3,2)$ <em> on the graph, then draw a straight line through both points</em>

See attachment for graph

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3 years ago

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Point Form:
(
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2
,
−
1
)
(
-
2
,
-
1
)
Equation Form:
x
=
−
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3 years ago

A recent poll of 700 people who work indoors found that 278 smoke. if the researchers want to be 98% confident of their results

Mice21 [21]

Answer:

We are given:

$\hat{p}=\frac{278}{700}=0.397$

$z_{\frac{0.02}{2}}=2.33$ is the critical value at 0.02 significance level

$E=0.035$ is the margin of error

Therefore, the required sample size is:

$n=\hat{p}(1-\hat{p}) \left(\frac{z_{\frac{0.02}{2}} }{E} \right )^{2}$

$=0.397(1-0.397) \left( \frac{2.33}{0.035} \right)^2$

$=0.239391 \times 4431.755102$

$=1060.922286 \approx 1061$

Therefore, the required sample size n = 1061

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4 years ago

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