Assume Allison, Bob, and Charisse are the only three buyers of oranges, and only three oranges can be supplied per day.
Refer to Table 7-5. If the market price of an orange is $0.65, then consumer surplus amounts to <u>$3.60</u>
<h3>What
is consumer surplus?</h3>
Consumers' surplus is a measure of consumer welfare and is defined as the excess of social valuation of product over the price actually paid. It is measured by the area of a triangle below a demand curve and above the observed price. Since there is willingness to pay.
Therefore, the correct answer is as given above.
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The complete question goes thus:
For each of three potential buyers of oranges, the table displays the willingness to pay for the first three oranges of the day. Assume Allison, Bob, and Charisse are the only three buyers of oranges, and only three oranges can be supplied per day.
Refer to Table 7-5. If the market price of an orange is $0.65, then consumer surplus amounts to________
The answer is C electrochemical potential.
Hope this helps.
Answer:
Since the output of consumption is most likely waste it is hard to track where the waste is going. Whereas with production theory the output is the product which goes to the consumer. This is much more easy to observe and is therefore "directly observable."
Explanation:
D) Social Roles. These are roles that Shellie's manager position entails that directly involve managing and working with people, which makes them her social roles. Shellie surely has other functions at the office, such as reviewing paychecks and resumes, and perhaps compiling expense reports. The examples listed above are social roles because they require her to work directly with the people in her office.
The function r(t)= 0.5 + t cos(πt³/80) is an illustration of a cosine function
The depth of water in the rain gauge increases by 1.466cm from t = 0 to t = 3
<h3>How to determine the increase in water depth?</h3>
The function is given as:
r(t)= 0.5 + t cos(πt³/80)
When t = 0, the depth of water is:
r(0)= 0.5 + 0 * cos(π *0³/80)
Evaluate
r(0) = 0.5
When t = 3, the depth of water is:
r(3)= 0.5 + 3 * cos(π *3³/80)
Evaluate
r(3)= 1.966
Calculate the difference (d) in the depths
d = r(3) - r(0)
So, we have:
d = 1.966 - 0.5
Evaluate
d = 1.466
Hence, the depth of water in the rain gauge increases by 1.466cm from t = 0 to t = 3
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