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3 years ago

How to find median with even amount of numbers?

1 answer:

8 0

Sort the numbers in ascending or descending order, then eliminate the greatest and least numbers until you're left with the middle two. The median is the average of the last two numbers.

For example, the median for the set $\{2,10,-1,4\}=\{-1,2,4,10\}$ is 3 because the middle two numbers are 2 and 4, and their average is $\dfrac{2+4}2=3$ .

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Write the equation in function form: 3y - 12x = 0

ivanzaharov [21]

Answer: 4x

Step-by-step explanation: Move all terms that don't contain y to the right side and solve. y = 4x

6 0

3 years ago

Read 2 more answers

Give the following equation in point slopr form, what is the slope of the line?

AVprozaik [17]

Answer:

Slope= 3

Step-by-step explanation:

y - 4= 3(x+6)

y - 4= 3x + 18 distributive property

y - 4(+4) = 3x + 18(+4)

cancel out the 4 with its oposite and apply to both sides.

y = 3x + 22 final answer

Remember the slope intersept equation... y=mx+b

m is slope

b means the y-intersept.

So the final slope of the line is 3. (demostrated by graph below)

Program for graph: Desmos

5 0

3 years ago

The ages of the people in attendance at the showing of an award-winning foreign film are shown below.

guapka [62]

Definition: A histogram visualises the distribution of data over a continuous interval or certain time period. Each bar in a histogram represents the tabulated frequency at each interval.

According to the given histogram,

0-20 years occur 15 times,

21-40 years occur 40 times,

41-60 years occur 40 times,

61-80 years occur 15 times.

This shows that the data is symmetrical and the majority of the attendees were between the ages of 21 and 60 (40 times).

Answer: correct choice is B.

5 0

3 years ago

Read 2 more answers

An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so

alexgriva [62]

Solution :

Let $p_1$ and $p_2$ represents the proportions of the seeds which germinate among the seeds planted in the soil containing $3\%$ and $5\%$ mushroom compost by weight respectively.

To test the null hypothesis $H_0: p_1=p_2$ against the alternate hypothesis $H_1:p_1 \neq p_2$ .

Let $\hat p_1, \hat p_2$ denotes the respective sample proportions and the $n_1, n_2$ represents the sample size respectively.

$$\hat p_1 = \frac{74}{155} = 0.477419$

$n_1=155$

$$p_2=\frac{86}{155}=0.554839$

$n_2=155$

The test statistic can be written as :

$$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}$

which under $H_0$ follows the standard normal distribution.

We reject $H_0$ at $0.05$ level of significance, if the P-value or if $|z_{obs}|>Z_{0.025}$

Now, the value of the test statistics = -1.368928

The critical value = $\pm 1.959964$

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

$=2 \times 0.085667$

= 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$ , so we fail to reject $H_0$ at $0.05$ level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the $\text{proportion}$ of the seeds that $\text{germinate differs}$ with the percent of the $\text{mushroom compost}$ in the soil.

8 0

3 years ago

Complete the proof. Prove: AUWX - AUW A) AAS B) ASA C)HL D) SAS

balu736 [363]

Answer:D) SAS

Step-by-step explanation:

USA test prep

8 0

3 years ago