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KatRina [158]
4 years ago
11

(2a^x +1/2 b^x)^2 thank you!!!!!!!!!!!!!!!!!!!1

Mathematics
1 answer:
kogti [31]4 years ago
3 0
Note that (a+b)^2 = a^2 + 2ab + b^2.

Therefore, 
                                                                              b^x         (b^x )^2
<span>(2a^x +1/2 b^x)^2 becomes (2a^x)^2 + 2(2a^x)(-------- ) + ------------
                                                                                 2               4

LCD is 4.  Thus, we have
                                             
            4 [ (2a^(2x) ] + 8</span>a^x*b^x + b^(2x)
<span>                                  </span>
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Answer:

Area= 64pi or 201.06

Circumference: 16pi or 50.265

Step-by-step explanation:

Area= \pi r^{2}

pi (8)^2 = 64pi or 201.06

Circumference= 2pir , 2(pi)8 = 16pi or 50.2

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What is the best estimate for the volume of the pyramid?
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Please help I been here for I hour
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What is the selling price per widget as a function of the
zalisa [80]

Answer:

1240 widgets

Step-by-step explanation:

<em>The value of the function at 870, the local maximum, is </em>

<em>= -0.02(870)2 + 34.80(870) - 4700 </em>

<em>= -0.02(756900) + 30276 - 4700 </em>

<em>=  -15138 + 25576 </em>

<em>= 10438 </em>

<em>  </em>

<em>So the vertex is (870, 10438) </em>

<em>  </em>

<em>The cost t the company to produce 870 widgets is  </em>

<em>C(870) = 4700 + 5.20(870) = 4700 + 4524 = 9224 </em>

<em>  </em>

<em>So, the cost of the widgets plus the profit must be equal to the total sales, which is divided by the number of widgets reveal their individual price. </em>

<em>(10438 + 9224)/870 = 19662/870 = $22.60 </em>

<em>  </em>

<em>P(x) = 7700 </em>

<em>- 0.02x2 + 34.80x - 4700 = 7700 </em>

<em>-0.02x2 + 34.80x -12400 = 0 </em>

<em>  </em>

<em>x = {-34.80 ± √[(34.80)2 - 4(-0.02)(-12400)]}/2(-0.02) </em>

<em>x = [-34.80 ± √(1211.04 - 992)]/(-0.04) </em>

<em>x = (-34.80 ± √219.04)/(-0.04) </em>

<em>x = (-34.80 ± 14.8)/(-0.04) </em>

<em>x = 870 ± 370 </em>

<em>so, $7700 in profits will be earned at either 500 widgets or </em><em>1240 widgets</em>

6 0
3 years ago
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