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Harman [31]
4 years ago
7

A red string of lights blinks once every 3 seconds while a string of blue lights blink once every 4 seconds. How many times will

both sets of lights blink at the same time in 60 seconds?
Mathematics
1 answer:
Helga [31]4 years ago
7 0
The string of red lights will blink 20 times and the blue lights will be 15 60 divided by 4 is 15 and 60 divided by 3 is 20
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A line is graphed through points at (4, 5) and (8 10). What is the ordered pair of the unit rate?
Phoenix [80]

Answer:

(2,4)

Step-by-step explanation:

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4 years ago
Which statement describes the transformation of figure 2 into figure 3?
AnnZ [28]

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2 reflection across the y axis

3 0
2 years ago
HELP ME PLEASE AND JUST GIVE ME THE ANSWER NO EXPLANATION
Arisa [49]

The <em>missing</em> end of the <em>line</em> segment \overline {GH} whose midpoint is M(x, y) = (5, 3) and known endpoint is G(x, y) = (1, -5) is the point H(x, y) = (9, 11).

<h3>How to locate the missing end of a line segment</h3>

In this question we know an end and a midpoint of a <em>line</em> segment. The <em>missing</em> end can be found from the following formula:

M(x, y) = G(x, y) + 0.5 · [H(x, y) - G(x, y)]

M(x, y) = 0.5 · G(x, y) + 0.5 · H(x, y)

0.5 · H(x, y) = M(x, y) - 0.5 · G(x, y)

H(x, y) = 2 · M(x, y) - G(x, y)     (1)

If we know that M(x, y) = (5, 3) and G(x, y) = (1, -5), then the coordinates of the point H are:

H(x, y) = 2 · (5, 3) - (1, -5)

H(x, y) = (10, 6) - (1, -5)

H(x, y) = (9, 11)

The <em>missing</em> end of the <em>line</em> segment \overline {GH} whose midpoint is M(x, y) = (5, 3) and known endpoint is G(x, y) = (1, -5) is the point H(x, y) = (9, 11).

To learn more on line segments: brainly.com/question/25727583

#SPJ1

3 0
2 years ago
Read 2 more answers
Choose all the functions that are NOT linear.
Zanzabum
A and E hope this helps
7 0
4 years ago
A peer is having difficulty finding angle measures using trigonometric ratios in a right triangle. Create an example to demonstr
frosja888 [35]
Please see diagram:
A right triangle has 3 main trigonometric ratios. These ratios are the relationships between different sides of the triangle, how large one side is compared to the other side. If you have every angle, in degrees, of a triangle, then you can figure out the relation between the lengths of the three sides. Additionally, you can figure out the value of the angles, given the sides of the triangle. 
In the diagram, we are interested in the trigonometric ratios with respect to angle a. 

You see in the diagram that sine, cosine, and tangeant are described as their ratios: (one way to remember: SohCahToa
sine = opposite / hypotenuse      
cosine = adjacent / hypotenuse                 
tangeant = opposite / adjacent. 

cosecant, secant, and cotangents are just the reciprocals of these ratios:
cosecant = 1 / sin 
secant = 1 / cosine
cotangeant = 1 / tangeant

8 0
3 years ago
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