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Free_Kalibri [48]
3 years ago
5

What is the answer for 6?

Mathematics
1 answer:
marusya05 [52]3 years ago
7 0
IS the answer ii and iv


and the other is y<5.3
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(32)2/5 RADICAL NOTATION
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There is a line through the origin that divides the region bounded by the parabola y=2x-4x^2 and the x-axis into two regions wit
shtirl [24]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

y = 7x - 4x² 

<span>7x - 4x² = 0 </span>

<span>x(7 - 4x) = 0 </span>

<span>x = 0, 7/4 </span>

<span>Find the area of the bounded region... </span>

<span>A = ∫ 7x - 4x² dx |(0 to 7/4) </span>

<span>A = 7/2 x² - 4/3 x³ |(0 to 7/4) </span>

<span>A = 7/2(7/4)² - 4/3(7/4)³ - 0 = 3.573 </span>

<span>Half of this area is 1.786, now set up an integral that is equal to this area but bounded by the parabola and the line going through the origin... </span>

<span>y = mx + c </span>

<span>c = 0 since it goes through the origin </span>

<span>The point where the line intersects the parabola we shall call (a, b) </span>

<span>y = mx ===> b = m(a) </span>

<span>Slope = m = b/a </span>

<span>Now we need to integrate from 0 to a to find the area bounded by the parabola and the line... </span>

<span>1.786 = ∫ 7x - 4x² - (b/a)x dx |(0 to a) </span>

<span>1.786 = (7/2)x² - (4/3)x³ - (b/2a)x² |(0 to a) </span>

<span>1.786 = (7/2)a² - (4/3)a³ - (b/2a)a² - 0 </span>

<span>1.786 = (7/2)a² - (4/3)a³ - b(a/2) </span>

<span>Remember that (a, b) is also a point on the parabola so y = 7x - 4x² ==> b = 7a - 4a² </span>
<span>Substitute... </span>

<span>1.786 = (7/2)a² - (4/3)a³ - (7a - 4a²)(a/2) </span>

<span>1.786 = (7/2)a² - (4/3)a³ - (7/2)a² + 2a³ </span>

<span>(2/3)a³ = 1.786 </span>

<span>a = ∛[(3/2)(1.786)] </span>

<span>a = 1.39 </span>

<span>b = 7(1.39) - 4(1.39)² = 2.00 </span>

<span>Slope = m = b/a = 2.00 / 1.39 = 1.44</span>

7 0
3 years ago
CAN SOMEONE PLEASE HELP ME WITH THIS ONE!
Fofino [41]
14/21 = 2/3 because you can divide them both by 7
3 0
3 years ago
Derive the first three (non-zero) terms of Taylor's series expansion for the function
mestny [16]

Answer:

We want to find the first 3 terms of the Taylor's series expansion for f(x) = sin(x) around x = 0.

Remember that a Taylor's series expansion of a function f(x) around the point x₀ is given by:

f(x) = f(x_0) + \frac{1}{2!}f'(x_0)*(x - x_0) + \frac{1}{3!}*f''(x_0)*(x - x0)^2 + ...

Where in the formula we have the first 3 terms of the expansion (but there are a lot more).

So, if:

f(x) = sin(x)

x₀ = 0

The terms are:

f(x_0) = sin(0) = 0

\frac{1}{2!}*f(x_0)'*(x - x_0) = \frac{1}{2} cos(0)*(x - 0) = x/2

\frac{1}{3!}*f(x_0)''*(x - x_0)^2 = \frac{1}{6}*-sin(0)*(x - 0)^2 = 0

\frac{1}{4!}*f(x_0)'''*(x - x_0)^3 = \frac{1}{24}*-cos(0)*(x- 0)^3 = -\frac{x^3}{24}

We already can see that the next term is zero (because when we derive the cos part, we will get a sin() that is zero when evaluated in x = 0), then the next non zero term is:

\frac{1}{6!}*f(x_0)''''*(x - x_0)^5 = \frac{1}{2*3*4*5*6} *(x - 0)^5 = \frac{x^5}{720}

Then we can write:

sin(x) = \frac{x}{2} - \frac{x^3}{24} + \frac{x^5}{720}

Evaluating this in x = 0.2, we get:

sin(0.2) = \frac{0.2}{2} - \frac{0.2^3}{24} + \frac{0.2^5}{720} = 0.099667

7 0
3 years ago
Ted researched the price of airline tickets and discovered a correlation between the price of a ticket and the number of miles t
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D) <span>the expected change in price of the ticket for each mile traveled</span>
3 0
4 years ago
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