1: Solve for either x or y in one of the equations. So x + y = -1 is y = -x -1
2: substitute the new equation in the opposite equation. So x - (-x - 1) = 7
3: distribute the negative. X + x + 1 = 7
4: combine like terms. 2x + 1 = 7
5: solve for x. Subtract 1 on both sides. 2x = 6
6: divide by 2 to get x by itself. X = 3
7: plug the new value of x into one of the ORIGINAL equations. 3 + y = -1
8: solve for y. Subtract 3 on both sides.
Y = -4
9: the solution is written as (x,y) so the solution would be (3, -4)
I got you hun!
27= 3x is the equation you will need
27 is the total the coach needs making it the total. Since each pack comes with 3 you will mutiply the amount of pack, or x, by 3.
X=9
we know this because if you divide 3 by 27 to get it on the other side we get 9. This means the coach needs to buy 9 packs of baseballs for the team.
27=3(9)
Hope this helps!
Answer:
89.03
Step-by-step explanation:
29x3.07=89.03
Answer:
length = 8
width = 4
Step-by-step explanation:
Area = length x breadth
Let x represent the width
length = x + 4
32 = x × (x + 4)
32 = x² + 4x
x² + 4x - 32 = 0
solving using quadratic equation =
(x² - 4x) -32 + 8x
x = 4 or -8
since width cannot be a negative number, we would use 4
Answer:
17
Step-by-step explanation:
Here in this question for finding the numbers that will divide 398, 436 and 542 leaving remainder 7, 11 and 15 respectively we have to first subtract the remainder of the following. By this step we find the highest common factor of the numbers.
And then the required number is the HCF of the following numbers that are formed when the remainder are subtracted from them.
Clearly, the required number is the HCF of the numbers 398−7=391,436−11=425, and, 542−15=527
We will find the HCF of 391, 425 and 527 by prime factorization method.
391=17×23425=52×17527=17×31
Hence, HCF of 391, 4250 and 527 is 17 because the greatest common factor from all the numbers is 17 only.
So we can say that the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively is 17.
Note: - whenever we face such a type of question the key concept for solving this question is whenever in the question it is asking about the largest number it divides. You should always think about the highest common factor i.e. HCF. we have to subtract remainder because you have to find a factor that means it should be perfectly divisible so to make divisible we subtract remainder. because remainder is the extra number so on subtracting remainder it becomes divisible.
