B because it is creating it
With would be 3.4
f(x)=3x^2-18x+10
a = 3, b = -18 and c = 10
The vertex of a parabola is in form a(x+d)^2 + e
d = b/2a = -18/2(3) = -18/6 = -3
e = c-b^2/4a = 10 - -18^2/4(3) = 10-27 = -17
Now the vertex form of the parabola becomes 3(x-3)^2 -17
Use the vertex form of the parabola in the vertex form of y = a(x-h)^2 +k
Where a = 3, h = -3 and k = -17
Now you have y = 3(x-(-3))^2 +(-17)
Simplify: y = 3(x+3)^2 -17
The vertex becomes the h and k values of (3,-17)
Answer:
46 cm
Step-by-step explanation:
Let p represent the length in cm of 1 bap'ai; let k represent the length in cm of 1 bok'ai. Then we have ...
12p +2k = 100
10p +10k = 100
Subtracting the second equation from 5 times the first, we get ...
5(12p +2k) -(10p +10k) = 5(100) -(100)
50p = 400
p = 8 . . . . cm
Then the second equation tells us ...
10(8) +10k = 100
10k = 20
k = 2 . . . . cm
Then 5p+3k = 5(8) +3(2) = 46 cm.
The distance 5 bap'ai and 3 bok'ai is 46 cm.
Answer:
650
Step-by-step explanation:
brainliest please
Answer:
2^5 *3
Step-by-step explanation:
You can solve this multiple ways but should get 2^5*3