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lord [1]
3 years ago
6

Suppose someone tells you that she has a triangle with sides having lengths 2.6, 8.1, and 8.6. Is this a right triangle? Why or

why not? Is there an angle in the triangle larger than 90 degree?
Mathematics
1 answer:
Elodia [21]3 years ago
8 0
First you check for Pythagoras'  Theorem.

Is  8.6² = 8.1²  + 2.6²  ? 
  
8.1²  + 2.6² = 65.61 + 6.76 = 72.37
8.6² =  73.96

8.1²  + 2.6²  ≠ 8.6² 

Since Pythagoras' Theorem is not satisfied it is not a right angled triangle.

The longest side is 8.6,  let's find the angle facing the longest side 8.6.

By cosine formula  CosA =  (b² + c² - a²) / (2bc)

CosA =  (2.6² + 8.1² - 8.6²) / (2*2.6*8.1) = -1.59/42.12 = -0.0377

A = Cos inverse (-0.0377) = 92.1 degrees

So there is  an angle is greater than 90 degrees.
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Find a. Round to the nearest tenth.
Kazeer [188]

9514 1404 393

Answer:

  21.8 cm

Step-by-step explanation:

A useful way to write the Law of Sines relation when solving for side lengths is ...

  a/sin(A) = b/sin(B)

Then the solution for 'a' is found by multiplying by sin(A):

  a = sin(A)(b/sin(B)) = b·sin(A)/sin(B)

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We need to know the angle A. Its value is ...

  A = 180° -75° -31.8° = 73.2°

Then the desired length is ...

  a = (22 cm)sin(73.2°)/sin(75°) ≈ (22 cm)(0.9573/0.9659)

  a ≈ 21.8 cm

_____

I like to use the longest side and largest angle in the equation when those are available. That is why I chose 75° and 22 cm.

6 0
3 years ago
What is the vertex of the quadratic function y=-(x-3)^2+4
cestrela7 [59]

Answer:

vertex = (3, 4 )

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

y = - (x - 3)² + 4 ← is in vertex form

with (h, k ) = (3, 4 ) ← vertex

5 0
3 years ago
PLEASE HELP PICTURE SHOWN CHECK ALL THAT APPLY
marusya05 [52]
To find the zeros set the factors on the numerator equal to zero and solve
(x - 1) = 0      x = 1
(x + 1) = 0      x = -1
5 0
3 years ago
Create a list of steps, in order, that will solve the following equation 1/4(x+5)^2-1=3
Paul [167]

Answer:

Add 1 to each side

Multiply each side by 4

Take the square root of each side

Subtract 5 from each side

Combine terms

Step-by-step explanation:

1/4(x+5)^2-1=3

Add 1 to each side

1/4(x+5)^2-1+1=3+1

1/4(x+5)^2=4

Multiply each side by 4

4*1/4(x+5)^2=4*4

(x+5)^2=16

Take the square root of each side

sqrt((x+5)^2)=±sqrt(16)

x+5 = ±4

Subtract 5 from each side

x+5-5 = -5  ±4

x = -5  ±4

Combine terms

x = -5+4       x = -5-4

x = -1            x = -9

7 0
3 years ago
Solve for the zeros of the quadratic function f(x) = x + 5 – 2x2.
harkovskaia [24]

Answer:

a= -2

b= 1

c= 5

b^2-4ac= 41

The quadratic function will have 2 real number zeros

Step-by-step explanation:

Edguinity

8 0
3 years ago
Read 2 more answers
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