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stira [4]
3 years ago
15

Insert <,> or = to make the sentence true. -1/3 , -2/5

Mathematics
2 answers:
choli [55]3 years ago
6 0
-1/3>-2/5 Because those fractions as decimals looks like this -0.3>-0.4
Mashcka [7]3 years ago
4 0

connexus:

1. 1.4

2. >

3. Associative Property of Multiplication

4. 1

5. -7

-hope this helps you guys :3

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A recent study estimated that 68% of US adults enjoy reading a book while relaxing. How many adults are required
Leno4ka [110]

Answer:

Step-by-step explanation:

236, did on edge

4 0
3 years ago
17 - 2n = 9 what’s the answer ?
BlackZzzverrR [31]

Step 1: Simplify both sides of the equation.

17−2n=9

17+−2n=9

−2n+17=9

Step 2: Subtract 17 from both sides.

−2n+17−17=9−17

−2n=−8

Step 3: Divide both sides by -2.

−2n−2=−8−2

n=4

8 0
3 years ago
HELP ME PLEASEEE ILL GIVE BRAINLIEST ITS DUE TODAY
nikdorinn [45]
Dang… I wish I can help.
6 0
3 years ago
There are 80 skittles in a bag you pick a handful of 12 purple 6 orange 3 red 5 green 4 yellow. How many red skittles do you exp
frozen [14]

Answer

12

Step-by-step explanation

there is 15 of each color  3 take away 15 equals 12 red skittles left

7 0
3 years ago
The augmented matrix of a system of equations has been transformed to an equivalent matrix in​ row-echelon form. Using​ x, y
jenyasd209 [6]

Answer: The system of equations is:

x + 2y + 2 = 4

y - 3z = 9

z = - 2

The solution is: x = -22; y = 15; z = -2;

Step-by-step explanation: ONe way of solving a system of equations is using the Gauss-Jordan Elimination.

The method consists in transforming the system into an augmented matrix, which is writing the system in form of a matrix and then into a <u>Row</u> <u>Echelon</u> <u>Form,</u> which satisfies the following conditions:

  • There is a row of all zeros at the bottom of the matrix;
  • The first non-zero element of any row is 1, which called leading role;
  • The leading row of the first row is to the right of the leading role of the previous row;

For this question, the matrix is a Row Echelon Form and is written as:

\left[\begin{array}{ccc}1&2&2\\0&1&3\\0&0&1\end{array}\right]\left[\begin{array}{ccc}4\\9\\-2\end{array}\right]

or in system form:

x + 2y + 2z = 4

       y + 3z = 9

               z = -2

Now, to determine the variables:

z = -2

y + 3(-2) = 9

y = 15

x + 30 - 4 = 4

x = - 22

The solution is (-22,15,-2).

4 0
4 years ago
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