Considering the first equation 15 × 0 = -36 + a
15 × 0 = 0
therefore, -36 + a =0
In the second equation
24 × 8 × 0 = 36 - b
Consider the LS
24 × 8 × 0 = 0
Therefore, 36 - b = 0
we are left with the two equations,
36 - b = 0
-36 + a = 0
then, we calculate the number that can be substituted to satisfy the two equations.
solving the equations
b = 36, and a = 36
Therefore, 36 is the number that can be used to substitute a and b in the equations
Answer:
9x^4+3x^2 -6
Step-by-step explanation:
(3x^2-2)(3x^2+3)
expand to remove the bracket
9x^4 + 9x^2 -6x^2 - 6
9x^4 + 3x^2- 6
Answer:
graph - A
Step-by-step explanation: