Use the discriminant to determine the number and type of solutions to the quadratic equation. Show all work for full credit.

Colin is painting figurines. He spends 20 minutes painting each figurine. After painting for 60 minutes, he still has 9 more fig

blagie [28]

Answer:

F(t)= - 0.05t+ 12

6 0

2 years ago

I REALLY NEED YOUR HELP DUE AT THE END OF CLASS.

shutvik [7]

Answer:

Type 2

Step-by-step explanation:

Equation of the line is:

y=2

slope is 0

4 0

3 years ago

Help pls if u can pls

Vadim26 [7]

Answer:

Infinite solutions.

Step-by-step explanation:

Let's solve your system by substitution.

3y=9x+15;3x−y=−5

Rewrite equations:

3x−y=−5;3y=9x+15

Step: Solve 3x−y=−5 for y:

3x−y=−5

3x−y+−3x=−5+−3x(Add -3x to both sides)

−y=−3x−5

−y −1 −1=−3x−5

(Divide both sides by -1)

y=3x+5

Step: Substitute 3x+5 for y in 3y=9x+15:

3y=9x+15

3(3x+5)=9x+15

9x+15=9x+15(Simplify both sides of the equation)

9x+15+−9x=9x+15+−9x(Add -9x to both sides)

15=15

15+−15=15+−15(Add -15 to both sides)

0=0

Hello lucker

8 0

3 years ago

Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into

Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = $(\frac{60\pi }{\pi+4}) in$

b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

b= $\frac{y}{4}$

Area of the square which is L² can now be said to be;

$A_S=(\frac{y}{4})^2 = \frac{y^2}{16}$

On the otherhand; let the radius (r) of the circle be;

2πr = 60-y

$r = \frac{60-y}{2\pi }$

Area of the circle which is πr² can now be;

$A_C= \pi (\frac{60-y}{2\pi } )^2$

$=( \frac{60-y}{4\pi } )^2$

Total Area (A);

A = $A_S+A_C$

= $\frac{y^2}{16} +(\frac{60-y}{4\pi } )^2$

For the smallest possible area; $\frac{dA}{dy}=0$

∴ $\frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0$

If we divide through with (2) and each entity move to the opposite side; we have:

$\frac{y}{18}=\frac{(60-y)}{2\pi}$

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

$y= \frac{240}{\pi+4}$

∴ since $y= \frac{240}{\pi+4}$ , we can determine for the length of the circle ;

60-y can now be;

= $60-\frac{240}{\pi+4}$

= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

also, the length of wire for the square (y) ; $y= (\frac{240}{\pi+4})in$

The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0

4 years ago

I need help trying to figure this out I think I have and answer but I want to make sure.

yKpoI14uk [10]

Answer:

34

Step-by-step explanation:

The mean is calculated as

mean = $\frac{frequency(midpoint)}{frequency}$

let x be the missing frequency, then

Total frequency × midpoint

= (16 × 2) + 7x + (20 × 12) + (10 × 17) = 32 + 7x + 240 + 170 = 442 + 7x

Total frequency = 16 + x + 20 + 10 = 46 + x, thus

$\frac{242+7x}{46+x}$ = 8.5 ( cross- multiply )

442 + 7x = 8.5(46 + x)

442 + 7x = 391 + 8.5x ( subtract 8.5x from both sides )

442 - 1.5x = 391 ( subtract 442 from both sides )

- 1.5x = - 51 ( divide both sides by - 1.5 )

x = 34

The missing frequency is 34

3 0

3 years ago