Answer:
Given distance=360 km.
Let the speed of the train be x km/hr.
Speed when increased by 5 km/hr =(x+5) km/hr
x
360
−
(x+5)
360
=1
x(x+5)
[360x+1800−360x]
=1
x
2
+5x−1800=0
x
2
+45x−40x−1800=0
x(x+45)−40(x+45)=0
(x−40)(x+45)=0
x=40,−45
The speed of the train is 40 km/hr.
Step-by-step explanation:
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