20% of your employees work part time

Mathematics

2 answers:

DerKrebs [107]3 years ago

4 0

C. 1/5 is the fraction of employees that work part time.

Mrrafil [7]3 years ago

3 0

Well, 20% is simply 20/100 that's fraction simplifies to 1/5. so your answer is c.1/5

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Evaluate the integral. (Assume a ≠ b. Remember to use absolute values where appropriate. Use C for the constant of integration.)

Bess [88]

Answer:

F(x)= 5*[ $\frac{x^{3} }{3}$ + (a*b)* $\frac{x^{2} }{2}$ + a*b*x + C.

Step-by-step explanation:

First step we aplicate distributive property to the function.

5*(x+a)*(x+b)= 5*[ $x^{2}$ +x*b+a*x+a*b]

5*[ $x^{2}$ +x*(b+a)+a*b]= f(x), where a, b are constant and a≠b

integrating we find ⇒∫f(x)*dx= F(x) + C, where C= integration´s constant

∫^5*[ $x^{2}$ +x*(a+b)+a*b]*dx, apply integral´s property

5*[∫ $x^{2}$ dx+∫(a*b)*x*dx + ∫a*b*dx], resolving the integrals

5*[ $\frac{x^{3} }{3}$ + (a*b)* $\frac{x^{2} }{2}$ + a*b*x

Finally we can write the function F(x)

F(x)= 5*[ $\frac{x^{3} }{3}$ + (a*b)* $\frac{x^{2} }{2}$ + a*b*x ]+ C.

4 0

3 years ago

Please help me!!! Will give 100 points. Will give BRAINILEST

Oksana_A [137]

Step-by-step explanation:

The shape of the new pizza must meet the conditions:

Be an irregular polygon (different sides and/or angles).
Have at least five sides.
Have the approximately the same area as a 14" diameter circle.
Fit in a 14⅛" × 14⅛" square.
Be divisible into 8-12 equal pieces.

For simplicity, I will choose a polygon with 5 sides (a pentagon), and I will use 2 right angles (a "house" shape).

Split the pentagon into a rectangle on bottom and triangle on top. If we cut the rectangle into 8 pieces like a regular pizza, and the triangle in half, we get 10 triangles.

Now we just need to figure out the dimensions. The area of a 14" circular pizza is:

A = πr²

A = π (7 in)²

A ≈ 154 in²

That means the area of each triangle slice needs to be 15.4 in². If we make the total width of the pentagon 14", then the width of each triangle is 7", and the height of each triangle is:

A = ½ bh

15.4 in² = ½ (7 in) h

h = 4.4 in

Which makes the total height of the pentagon 3h = 13.2 in.

So, our 13.2" × 14" pentagon has at least 5 sides, is irregular, has the same area as a 14" diameter circle, fits in a 14⅛" × 14⅛" square, and can be divided into 8-12 equal pieces.

Of course, there are many possible solutions. This is just one way.