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lesya692 [45]
3 years ago
12

What is the range of the function represented by this graph? the graph of a quadratic function with a minimum value at the point

(-3,1)
Mathematics
1 answer:
tatiyna3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

The minimum is at the vertex (- 3, 1 ), that is y = 1

Since the graph is a minimum then it opens vertically up U

The range of the values of y are therefore

range [ 1, ∞ )

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I am thinking of a number. i will add four and then multiply it by five. the answer will be thirty five. whats the number?
kodGreya [7K]

Answer:

B. 3

Step-by-step explanation:

Let's make an equation for this. Our unknown number is x.

x

We are adding 4.

x + 4

Then multiplying by 5.

(x + 4) • 5

It will equal 35.

(x + 4) • 5 = 35

To solve this, divide both sides by 5.

(x + 4) = 7

Now subtract 4 from both sides.

x = 3

This is your answer.

Check this by plugging it back into our original equation.

(x + 4) • 5 = 35

(3 + 4) • 5 = 35

7 • 5 = 35

35 = 35

Your answer is correct.

Hope this helps!

3 0
2 years ago
Write the equation of the line that passes through the points (2,0) and (1,-2)
Darya [45]

Answer:

y

=

2

x

−

1

Explanation:

First, we need to determine the slope of the line. The formula for determining the slope of a line is:

m

=

y

2

−

y

1

x

2

−

x

1

where

m

is the slope and the x and y terms are for the points:

(

x

1

,

y

1

)

and

(

x

2

,

y

2

)

For this problem the slope is:

m

=

3

−

−

1

2

−

0

m

=

3

+

1

2

m

=

4

2

m

=

2

Now, selecting one of the points we can use the point slope formula to find the equation.

The point slope formula is:

y

−

y

1

=

m

(

x

−

x

1

)

Substituting one of our points gives:

y

−

−

1

=

2

(

x

−

0

)

y

+

1

=

2

x

Solving for

y

to put this in standard form gives:

y

+

1

−

1

=

2

x

−

1

y

+

0

=

2

x

−

1

y

=

2

x

−

1

Answer linky

=

2

x

−

1

Explanation:

First, we need to determine the slope of the line. The formula for determining the slope of a line is:

m

=

y

2

−

y

1

x

2

−

x

1

where

m

is the slope and the x and y terms are for the points:

(

x

1

,

y

1

)

and

(

x

2

,

y

2

)

For this problem the slope is:

m

=

3

−

−

1

2

−

0

m

=

3

+

1

2

m

=

4

2

m

=

2

Now, selecting one of the points we can use the point slope formula to find the equation.

The point slope formula is:

y

−

y

1

=

m

(

x

−

x

1

)

Substituting one of our points gives:

y

−

−

1

=

2

(

x

−

0

)

y

+

1

=

2

x

Solving for

y

to put this in standard form gives:

y

+

1

−

1

=

2

x

−

1

y

+

0

=

2

x

−

1

y

=

2

x

−

1

Answer link

4 0
2 years ago
Please help solve this​
Oksi-84 [34.3K]
The answer is [3]. :))
8 0
2 years ago
Read 2 more answers
A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is ______ units. The poi
nalin [4]
Circle formula
(x-h)^2+(y-k)^2=r^2 where (h,k) is the center
and r=radius

to find the radius
we are given one of the points and the center
distnace from them is the radius
distance formula
D=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}
points (-3,2) and (1,5)
D=\sqrt{(1-(-3))^{2}+(5-2)^{2}}
D=\sqrt{(4)^{2}+(3)^{2}}
D=\sqrt{16+9}
D=\sqrt{25}
D=5

center is -3,2
r=5
input
(x-(-3))^2+(y-2)^2=5^2
(x+3)^2+(y-2)^2=25 is equation
radius =5
input -7 for x and solve for y
(-7+3)^2+(y-2)^2=25
(-4)^2+(y-2)^2=25
16+(y-2)^2=25
minus 16
(y-2)^2=9
sqqrt
y-2=+/-3
add 2
y=2+/-3
y=5 or -1

the point (-7,5) and (7,-1) lie on this circle



radius=5 units
the points (-7,5) and (-7,1) lie on this circle

3 0
3 years ago
Write as an algebraic expression <br><br>17 decreased by x​
Lerok [7]
The correct answer is 17-x
8 0
2 years ago
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