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Allisa [31]
3 years ago
14

What numbers add up to -5 and multiply to get -90

Mathematics
2 answers:
vlada-n [284]3 years ago
6 0
You don't say <em>how many</em> numbers you want to do that with.

If you want just two numbers, then they're  <em>+7.3107</em>  and  <em>-12.3107</em> .
(Those are rounded, not exact.)

I took a quick look among the factors of 90, looking for sets of <em>3 numbers</em>
that would do it, and I couldn't find any.
Molodets [167]3 years ago
3 0
Let
x-------> the first number
y-------> the second number

we know that

x+y=-5 \\ x=-5-y equation 1

x*y=-90 equation 2

substitute the equation 1 in equation 2

[-5-y]*y=-90 \\ -5y- y^{2} =-90 \\ y^{2} +5y-90=0

using a graphical tool to resolve the second order equation
see the attached figure
the numbers are
-12.311
7.311

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What is the 1st quartile in the data set 65 90 100 72 88 55 73
dem82 [27]
Im pretty sure the answer is 65
7 0
3 years ago
Determine whether each expression is equivalent to 49^2t – 0.5.
vampirchik [111]

Answer:

None of the expression are equivalent to 49^{(2t - 0.5)}

Step-by-step explanation:

Given

49^{(2t - 0.5)}

Required

Find its equivalents

We start by expanding the given expression

49^{(2t - 0.5)}

Expand 49

(7^2)^{(2t - 0.5)}

7^2^{(2t - 0.5)}

Using laws of indices: (a^m)^n = a^{mn}

7^{(2*2t - 2*0.5)}

7^{(4t - 1)}

This implies that; each of the following options A,B and C must be equivalent to 49^{(2t - 0.5)} or alternatively, 7^{(4t - 1)}

A. \frac{7^{2t}}{49^{0.5}}

Using law of indices which states;

a^{mn} = (a^m)^n

Applying this law to the numerator; we have

\frac{(7^{2})^{t}}{49^{0.5}}

Expand expression in bracket

\frac{(7 * 7)^{t}}{49^{0.5}}

\frac{49^{t}}{49^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{49^{t}}{49^{0.5}} becomes

49^{t-0.5}}

This is not equivalent to 49^{(2t - 0.5)}

B. \frac{49^{2t}}{7^{0.5}}

Expand numerator

\frac{(7*7)^{2t}}{7^{0.5}}

\frac{(7^2)^{2t}}{7^{0.5}}

Using law of indices which states;

(a^m)^n = a^{mn}

Applying this law to the numerator; we have

\frac{7^{2*2t}}{7^{0.5}}

\frac{7^{4t}}{7^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{7^{4t}}{7^{0.5}} = 7^{4t - 0.5}

This is also not equivalent to 49^{(2t - 0.5)}

C. 7^{2t}\ *\ 49^{0.5}

7^{2t}\ *\ (7^2)^{0.5}

7^{2t}\ *\ 7^{2*0.5}

7^{2t}\ *\ 7^{1}

Using law of indices which states;

a^m*a^n = a^{m+n}

7^{2t+ 1}

This is also not equivalent to 49^{(2t - 0.5)}

6 0
3 years ago
OK PLEASE HELP ME GUYS I ALWAYS HELP YOU so here it is
gtnhenbr [62]
F=P(1/2)^(t/h)
F=future amount
P=present amount
t=time elapsed
h=legnth of half life

P=96
t=2
h=1
F=96(1/2)^(2/1)
F=96(1/2)^2
F=96(1/4)
F=96/4
F=24 grams



grow by 35%
compound interest
F=P(1+rate)^time
F=95000(1+0.35)^10
F=95000(1.35)^10
F=95000(20.106555868618)
F=1910122.9075187  
8 0
2 years ago
obtain the equation of two points passing of lines 4x-3y-1=0 and 2x-3y+3=0 and equally inclined to the axes​
klasskru [66]

Answer:By 8(4)P.5, the slope of the line equally inclined to axes is tan(±45  

o

)=±1. Hence by P+λQ=0,

5λ+3

2λ+4

​

=±1

⇒λ=  

3

1

​

,−1. Putting for λ, the two lines are

x−y=0,x+y−2=0.

Was this answer helpful

8 0
2 years ago
Find the ratio in simplest form.<br> 30:6
Norma-Jean [14]
5:1 divide both by 6

7 0
3 years ago
Read 2 more answers
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