20 POINTS!!!!!!!!!!!!!!!!! DESPERATE HELP IM GOING TO DIE IF I DONT GET HELP PLZZZZZZZZZZZZZZZZZZZZZZZ

Mathematics

2 answers:

Delvig [45]4 years ago

6 0

The answer is only on the board it’s the same exact way put it in the order as you see it

CaHeK987 [17]4 years ago

3 0

Answer:

no.

Step-by-step explanation:

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Jessica's is making $300 less than four times what she was making when she started working. Let s represent her

vichka [17]

Answer:

4s-300= Jessica's current salary

8 0

4 years ago

Can someone help me out?

White raven [17]

Answer: 15

Step-by-step explanation:

=(−5−4)2+(−4−8)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√

d=(−5−4)2+(−4−8)2

=(−9)2+(−12)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾√

d=(−9)2+(−12)2

=81+144‾‾‾‾‾‾‾‾‾√

d=81+144

=2‾√25

d=225

=15

7 0

3 years ago

The isotope samarium-151 decays into europium-151, with a half-life of around 96.6 years. A rock contains 5 grams of samarium-15

Olegator [25]

Part A:

The amount of substance left of a radioactive substance with a half life $t_{ \frac{1}{2} }$ and amount of initial substance $N_0$ is given by

$N(t)=N_0\left( \frac{1}{2} \right)^{ \frac{t}{t_{ \frac{1}{2} }} }$

Given that the isotope samarium-151 has a half-life of around 96.6 years and the rock contains 5 grams of samarium-151 when it reaches its closure temperature, and it contains 0.625 grams when it is discovered.

The time since the rock reached its closure temperature is obtained as follows:

$0.625=5\left( \frac{1}{2} \right)^{ \frac{t}{96.6} } \\ \\ \Rightarrow\left( \frac{1}{2} \right)^{ \frac{t}{96.6} }= \frac{0.625}{5} =0.125 \\ \\ \Rightarrow\frac{t}{96.6}\log{ \frac{1}{2} }=\log0.125 \\ \\ \Rightarrow\frac{t}{96.6}= \frac{\log0.125}{\log{ \frac{1}{2} }} =3 \\ \\ \Rightarrow t=3(96.6)=289.8$

Therefore, the time since the rock reached its closure temperature is 289.8 years.

Part B:

Given that the rock contains 5 grams of samarium-151 when it reaches its closure temperature, and it contains 0.625 grams when it is discovered. The number of grams of europium-151 when the rock was discovered is 5 - 0.625 = 4.375

7 0

4 years ago

What appears to be the domain of the part of the exponential function graphed on the grid

Aleksandr [31]

Answer:

domain/4^6x7graph/7^x+6

Step-by-step explanation:

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4 years ago

Calculate the average rate of change of the given function f over the intervals [a, a + h] where h = 1, 0.1, 0.01, 0.001, and 0.

Delicious77 [7]

Step-by-step explanation: