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galina1969 [7]
4 years ago
14

Who wants 50 points...........

Mathematics
2 answers:
Dmitrij [34]4 years ago
4 0

Answer:

I want 50 points

Step-by-step explanation:

Nothing

uranmaximum [27]4 years ago
4 0
Meeee hahaha lolololol
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H(x) = –23 – 5, find h(-2)
adelina 88 [10]

Answer:

h=14

Step-by-step explanation:

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3 years ago
What is 5×20+2raised to the power 2​
Neporo4naja [7]

Answer:

10,404

Step-by-step explanation:

5x20+2=102

102^2=102x102=10,404

7 0
3 years ago
The equation for a parabola has the form y = ax2 + bx + c, where a, b, and c are constants and a ≠ 0. find an equation for the p
sattari [20]
To solve the problem, substitute the given points for x in the given equation to get

-10=(-1)^2a+(-1)b+c\Rightarrow-10=a-b+c \\ -6=(1)^2a+(1)b+c\Rightarrow-6=a+b+c \\ -13=(2)^2a+(2)b+c\Rightarrow-13=4a+2b+c

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Therefore, the required equation is

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7 0
3 years ago
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. y 2 ( y 2 − 4 ) = x 2 ( x
yawa3891 [41]

Answer:

y = -2

Step-by-step explanation:

To find the equation of the tangent we apply implicit differentiation, and then we take apart dy/dx

The equation is

y^2(y^2-4)=x^2(x^2-5)

implicit differentiation give us

\frac{d}{dx}[y^2(y^2-4)=x^2(x^2-5)]\\\\2y\frac{dy}{dx}(y^2-4)+y^2(2y\frac{dy}{dx})=2x(x^2-5)+x^2(2x)\\\\4y^3\frac{dy}{dx}-8y\frac{dy}{dx}=2x^3-10x+2x^3\\\\\frac{dy}{dx}=\frac{4x^3-10x}{4y^3-8y}

But we know that

m=\frac{dy}{dx}\\y=mx+b

Hence, for the point (0,-2) and by replacing for dy/dx

m=\frac{dy}{dx}_{(0,-2)}=\frac{4(0)+10(0)}{4(-2)^3-8(-2)}=0

Hence m=0, that is, the tangent line to the point is a horizontal line that cross the y axis for y=-2. The equation is:

y=(0)x+b = -2

HOPE  THIS HELPS!!

4 0
4 years ago
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andrey2020 [161]
8 x 3 = 24
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3 years ago
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