The rule would be ~y=4x+3~
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Answer:
88.51 is the minimum score needed to receive a grade of A.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 73
Standard Deviation, σ = 11
We are given that the distribution of exam grades is a bell shaped distribution that is a normal distribution.
Formula:

We have to find the value of x such that the probability is 0.0793.
Calculation the value from standard normal z table, we have,

Hence, 88.51 is the minimum score needed to receive a grade of A.
Answer:
Your answer would be B: $25.20
24 x 5% is 1.2
$24 + 1.2 is 25.2
Step-by-step explanation: