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fiasKO [112]
4 years ago
5

Explain the error in the solution below. What additional step needs to be completed? log x – log53 = 2log53 log x = 3log53 log x

= log533 x = 27
Mathematics
2 answers:
Pani-rosa [81]4 years ago
5 0
The bases of the logarithms are not the same.The one-to-one property does not apply when the bases are not the same.<span>The change of base formula should have been used to write the logarithms with the same base. 
I just checked it on Edge</span>
frez [133]4 years ago
5 0

Answer:

Error is in the step 3,

From step 4 to 9 is the required steps.

Step-by-step explanation:

Given : Solution below,

\log x -\log_5 3 = 2\log_5 3\\\log x = 3\log_5 3\\\log x = \log_5 33\\x = 27

To find : The error in the solution and what additional step needs to be completed?

Solution : The mistake is in the step 3 and additional step need to be added after it.

So we proceed it by starting,

Step 1 - \log x -\log_5 3 = 2\log_5 3

Step 2 - \log x = 3\log_5 3

Step 3 - \log x =\log_5 3^3

Step 4 - \log x=\log_5 27

Applying change base rule of logarithmic,

\log_b a=\frac{\log a}{\log b}

Step 5 - \log x=\frac{\log 27}{\log 5}

Step 6 - \log x=\frac{1.431}{0.698}

Step 7 - \log x=2.050

Step 8 - x=10^{2.050}

Step 9 - x=112.20

From step 4 to 9 is the required steps.

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What is the simplified form of the following expression? 2√27+√12-3√3-2√12
LiRa [457]

Answer:

√3

Step-by-step explanation:

The given expression to be simplified is

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}

but

2 \sqrt{27}=2\sqrt{9 \times 3}=2 \times \sqrt{9}\times \sqrt{3}=2 \times 3 \times\sqrt{3}=6 \sqrt{3}

\sqrt{12}=\sqrt{4\times3}= \sqrt{4}\times \sqrt{3}=2\sqrt{3}

Since √12=2√3,this implies that,

2\sqrt{12}=2\times2\sqrt{3}=4 \sqrt{3}

Therefore,

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}=6\sqrt{3}+2\sqrt{3}-3 \sqrt{3} -4\sqrt{3}

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The simplified form of ,

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12} is √3

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