Answer:
return values.remove() + values.remove();
Explanation:
The appropriate expression to complete the method, which is designed to return the sum of the two smallest values in the parameter array number is indicated below in bold font :
public static int
sumTwoLowestElements(int[] numbers)
{
PriorityQueue values = new PriorityQueue<>();
for (int num: numbers)
{ values.add(num);
}
return values.remove() + values.remove();
}
The return statementin programming is often used when a function is ready to return a value to its caller.
Answer:
// program in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// string array
string m[3];
// array to store rainfall
double rainfall[3];
// variables
double avg_rainfall,sum=0;
for(int i=0;i<3;i++)
{
cout<<"Enter name of month "<<i+1<<" :";
// read month name
cin>>m[i];
cout<<"Enter rainfall (inches) in month "<<i+1<<" :";
// read rainfall
cin>>rainfall[i];
// sum of rainfall
sum+=rainfall[i];
}
// Average rainfall
avg_rainfall=sum/3;
// print Average rainfall
cout<<"Average rainfall for "<<m[0]<<","<<m[1]<<","<<m[2]<<" is "<<avg_rainfall<<" inches."<<endl;
return 0;
}
Explanation:
Create string array "m" to store name of month and double array "rainfall" to store rainfall. Read name of 3 months and rainfall in that month.Find the sum of all the rainfall and the average rainfall.Print the average rainfall of 3 months.
Output:
Enter rainfall (inches) in month 2 :45
Enter name of month 3 :july
Enter rainfall (inches) in month 3 :43
Average rainfall for may,june,july is 42.6667 inches.
Answer:
A
Explanation:
The answer is A mate, if you need any help let me know please
Program Area_Circle;
Uses Crt;
Const
Pi = 3.1416;
Var
Radius : Integer;
Area : Real;
Begin
Clrscr;
Writeln('Area of a Circle Solver');
Writeln;
Write('Enter the Radius of the Circle : ');
Readln(Radius);
Area := (Pi * Radius * Radius);
Writeln;
Writeln('The Area of the Circle is ' ,Area:8:2,'.');
Writeln;
Writeln('Program Executed');
Readln;
End.
Hope this helps!
