The terms in which value of x when substituted leaves final value of p(x) = "0".
Here, x - 2 is factor. So value of x is 2.
Substituting value of x we get,
p(x) = x3 - 3x + 5a
p(2) = 2*3 - 3(2) + 5a
0+ 8-6 + 5a
-2 = 5a
a= -0.4
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The slope of the line will be equal to 30.
Slope of a line may be defined as the steepness of a curve. Slope of line can be positive, negative or zero. Slope of a line is used to determine the equation of the line which is given as y = mx + b where m is the slope, b is y intercept and x and y are independent and dependent variables respectively. The slope of a line on points (x₁, y₁) and (x₂, y₂) is given by the formula, m = y₂ - y₁/x₂ - x₁.
According to the question the value of points is (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 60).
Now, the slope can be calculated as
m = (60 - 0)/(2 - 0)
=> m = 60/2
=> m = 30 which is the required slope.
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Answer:
WHERE IS THE TABLE
Step-by-step explanation:
The answer is 8 because 12 plus 4 is 16, and then 16 minus 8 is 8
Answer:
x = -2
y = -1
(-2, -1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
- Solving systems of equations by graphing
Step-by-step explanation:
<u>Step 1: Define systems</u>
y = x + 1
3x + 3y = -9
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 3x + 3(x + 1) = -9
- Distribute 3: 3x + 3x + 3 = -9
- Combine like terms: 6x + 3 = -9
- Isolate <em>x</em> term: 6x = -12
- Isolate <em>x</em>: x = -2
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = x + 1
- Substitute in <em>x</em>: y = -2 + 1
- Add: y = -1
<u>Step 4: Graph systems</u>
<em>Check the solution set.</em>