Answer:
1st= 47/7 or 6.71
2nd= 48/7 or 6.857
Step-by-step explanation:
1st number =X and 2nd number = Y
According to question, X+7=2Y
20+Y=4X
X=2Y-7 (from 1st condition)
putting in it second
20+Y=4(2Y-7)
20+Y=8Y-28
20+28=8Y-Y
48=7Y
Y=48/7
so X=2(48/7)-7
=96-49/7
47/7
Answer:
a) S = {1, 2, 3}
b) P(odd number) = 
c) No
d) Yes
Step-by-step explanation:
a) The sample space is the set of all possible outcomes. By definition, the elements of a set should not be repeated. Hence, the sample space S = {1, 2, 3}
However, the sample is not equiprobable because each element has different probabilities.
b) P(odd number) = 
Note that the odd numbers are 1 (on three faces) and 3 (on one face).
c) The fact the die has been biased does not change the possible outcomes. It only changes the probability of getting any given number.
d) Because the 3-face has been loaded, this probability changes. In fact, it is calculated thus:
Let's assume the probability for 1 or 2 is
. Then that of 3 is
(because it is twice the others). The sum of probabilities must be 1.



P(odd number) =
Prob(1) + Prob(3)
=
= 
Answer:
-x+4
Step-by-step explanation:
-1(x-4) any expression multipled by 1 remains the same
-(x-4) remove the parenthesis
-x-4
Answer:
Wow Ashley I see you keep looking for the answers.
Step-by-step explanation:
This is the second time I have seen you looking for the answers on the internet, I am now thinking about giving you a zero for this week's homework. Please refrain from copying because I do not want to give you a bad score.
They bought 8 orchestra seats and 6 mezzanine seats.
Step-by-step explanation:
Cost of one orchestra seat = $42
Cost of one mezzanine seat = $25
No. of people = 14
Amount spent = $486
Let,
x be the number of orchestra seats
y be the number of mezzanine seats
According to given statement;
x+y=14 Eqn 1
42x+25y=486 Eqn 2
Multiplying Eqn 1 by 25;

Subtracting Eqn 3 from Eqn 2 to eliminate y;

Dividing both sides by 17

Putting x=8 in Eqn 1

They bought 8 orchestra seats and 6 mezzanine seats.
Keywords: linear equation, elimination method
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