Answer:
9
Step-by-step explanation:
You do parenthesis first so 1+2=3
Then you do division 6 divided by 2=3
Then you will multiply 3 by 3 so 9
This is known as pemdas
P=parenthesis
E=exponents
MD=multiplication and division you do it left to right so if division is in front of multiplication then you do division
As=Addition and subtraction is also left to right
490
Step-by-step explanation:
4333333
67
8
Scalene triangle,,,,,,,, a triangle that no side is equivalent to to another
#1 Mrs. Garcia is making 50 snacks for her 5th grade class. If she uses four 1-kilogram bags of dried fruit, how many of grams of fruit will she use for each snack?
1 kilogram is equal to 1000 grams.
4 kilograms is equal to 4000 grams.
You would need to divide the 4000 total grams by the 50 snack to get how many grams would be in each snack.
So you would do..
4000grams/50snacks = 80 grams each snack.
#3 Toni's recipe also calls for seasonings. She needs to stir in 215 milligrams of pepper and 437 milligrams of salt. What is the difference between the total amount of seasonings and 1 gram?
215 milligrams is equal to 0.215 grams
437 milligrams is equal to 0.437 grams
So you would add these two together
0.215 + 0.437 = 0.652 grams
Then to find the difference you would subtract 0.652 grams from 1 gram
1 - 0.652 = 0.348
0.348 is the difference.
Answer:
1. D. 20, 30, and 50
2. A. 86
3. B. 94
Step-by-step explanation:
1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.
The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.
Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.
Thus:
Q1 = (85 + 87)/2 = 86
Q3 = (93 + 95)/2 = 94
IQR = Q3 - Q1 = 94 - 86
IQR = 8
Outliers in the data set are data values below the lower limit or above the upper limit.
Let's find the lower and upper limit.
Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74
The data values below the lower limit (74) are 20, 30, and 50
Let's see if we have any data value above the upper limit.
Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106
No data value is above 106.
Therefore, the only outliers of the data set are:
D. 20, 30, and 50
2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.
Thus:
Q1 = (85 + 87)/2 = 86
3. Q3 = (93 + 95)/2 = 94
