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Flura [38]
3 years ago
7

I WILL AWARD BRAINLIEST!! PLEASE HELP!!

Mathematics
1 answer:
eimsori [14]3 years ago
6 0

Answer:

 A(...; 9)

x = 57/7

 B(4; ...)

y = 16/5

m = 7/5

Step-by-step explanation:

7x−5y=12

For point  A(...; 9)

We know y = 9

Substitute it in

7x−5(9)=12

7x -45= 12

Add 45 to each side

7x-45+45=12+45

7x = 57

Divide by 7

7x/7 = 57/7

x = 57/7

For point  B(4; ...)

We know x=4

Substitute it in

7(4)-5y =12

28 - 5y =12

Subtract 28 from each side

28-28 -5y =12-28

-5y =-16

Divide by -5

-5y/-5 = -16/-5

y = 16/5

Now we need to find the slope by solving the equation for y

7x -5y = 12

Subtract 7x

-5y=  -7x +12

Divide by -5

-5y=  -7x +12

-5y/-5 = -7x/-5 +12/-5

y = 7/5 x -12/5

This is in the form y = mx +b where m is the slope

m = 7/5

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Answer:

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Step-by-step explanation:

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3 years ago
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Solve 73 make sure to also define the limits in the parts a and b
Aleks04 [339]

73.

f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}

a)

\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3

b)

Since we can't divide by zero, we need to find when:

x^4-2x^2+144=0

But before, we can factor the numerator and the denominator:

\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}

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\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}

so, for x = -3:

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For x = 4:

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Tresset [83]
<h2>Hello!</h2>

The answer is:

The expression for the number of sweets that Sara and Tim have now, are:

Sara=(17-x)Sweets\\\\Tim=\frac{(24+x)Sweets}{2}

<h2>Why?</h2>

To write the expressions for the number of sweets that Sara and Tim have now, we need to follow the next steps:

Sara starts with 24 sweets and Tim starts with 24 sweets

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