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4vir4ik [10]
4 years ago
15

Is 5.787787778... a rational or irrational number?

Mathematics
2 answers:
loris [4]4 years ago
4 0

Answer:

Irrational

Step-by-step explanation:

Igoryamba4 years ago
3 0

Answer:

irrational

Step-by-step explanation:

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Write an equation for the sum of 14 and a number is equal to 17
Troyanec [42]
14 + x is the sum of 14 and a number

=17 is equal to 17

put it together and you get 14+x=17
3 0
3 years ago
Read 2 more answers
The volume of a sphere is a function of its radius. V equals 4 over 3 πr cubed . Evaluate the function for the volume of a volle
Nataly_w [17]

Answer:

The answer to your questin is:  V = 5276.7 cm³

Step-by-step explanation:

Data

radius = 10.8 cm

Volume = ?

Formula

                V = \frac{4}{3} \pi  r^{3}

                V = \frac{4}{3} \pi  (10.8)^{3}

                      V = 5276.7 cm³

4 0
3 years ago
A wall 15 m long, 30 cm wide and 4 m high is made of bricks, each measuring
schepotkina [342]
L = 15m = 1500cm
b= 30cm
h= 4m= 400cm



So, total volume of the wall= l×b×h
= 1500×30×400= 1,80,00,000 cm^3


Now, volume of one brick= 22×12.5×7.5= 2062.5 cm^3


Volume of wall containing only bricks= total volume of the wall - volume of wall containing mortar
= 1,80,00,000 - (1,80,00,000 × 1/12)
= 1,65,00,000 cm^3


So, no. of bricks = volume of wall containing bricks ÷ volume of one brick
= 1,65,00,000 ÷ 2062.5
= 8000 bricks.
4 0
3 years ago
Is the function y=<br> 2<br> 5<br> x2+<br> 7<br> 10<br> x–6 linear or nonlinear?
Andru [333]

Answer:

Step-by-step explanation:

8 0
3 years ago
Somebody had a seizure while making this question, please help ​
marissa [1.9K]

Check the picture below.

\textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}asn ~~ \begin{cases} a=apothem\\ n=\stackrel{side's}{number}\\ s=\stackrel{side's}{length}\\[-0.5em] \hrulefill\\ a=7\\ s=8.1\\ n=6 \end{cases}\implies \stackrel{\textit{area of the hexagonal base}}{A=\cfrac{1}{2}(7)(8.1)(6)} \\\\[-0.35em] ~\dotfill

\textit{volume of a prism}\\\\ V=Bh ~~ \begin{cases} B=\stackrel{base's}{area}\\ h=height\\[-0.5em] \hrulefill\\ B=\frac{1}{2}(7)(8.1)(6)\\ V=3572.1 \end{cases}\implies 3572.1=\cfrac{1}{2}(7)(8.1)(6)h \\\\\\ 3572.1=170.1h\implies \cfrac{3572.1}{170.1}=h\implies \boxed{21=h}

well, the length of the tunnel is "h", now two 8 meters cars, that's 8+8=16 meters plus a 3 meter connector between them, that's 16 + 3 = 19 meters, can those two cars connected like so fit inside the tunnel? sure thing, "h" can fit 19 meters just fine.

3 0
2 years ago
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