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enot [183]
3 years ago
9

A) 1 b) -20 c) 20 d) 7

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
3 0

f(x)=x^2;\ g(x)=x-3\\\\(g\ \circ\ f)(x)=(x^2)-4=x^2-3\\\\\text{Put x = -2 to the equation}\\\\(g\ \circ\ f)(-2)=(-2)^2-3=4-3=1\to\boxed{a)}

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<u>Given</u>:

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