3 years ago

A) 1 b) -20 c) 20 d) 7

1 answer:

3 0

$f(x)=x^2;\ g(x)=x-3\\\\(g\ \circ\ f)(x)=(x^2)-4=x^2-3\\\\\text{Put x = -2 to the equation}\\\\(g\ \circ\ f)(-2)=(-2)^2-3=4-3=1\to\boxed{a)}$

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