Answer:
Difference between the approximation and the actual value of f′(0.5) is 0.4330
Step-by-step explanation:
As complete question is not give, so considering the most relevant question to given statement in Fig below.
from table
x 0 1
f(x) 1 2
f'(0.5)=?
from numerical differentiation
Given function is
Differentiating w.r.to x
Difference between the approximation and the actual value of f′(0.5) is 0.4330
Answer:
The solution is r=40.
Step-by-step explanation:
First, we identify the parts of the division:
"r" is the dividend of the division.
10 is the divisor
4 is the quotient.
To get the value of "r", we have to make a tape diagram where the divisor represents the number of equal-sized parts (boxes) and the quotient represents de quantity inside the boxes.
The tape diagram is made of 10 equal-sized parts of 4.
So the result is 10×4=40. The value of "r" is 40.
(See attached picture)
Answer:
Step-by-step explanation:
Find attached the solution
