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3 years ago

8

Tonight,Harry has only 3/4 hour to run.He wants to run to the lake,which is 2 miles away.Would he have enough time to run to the

lake and back?

2 answers:

aliya0001 [1]3 years ago

7 0

Answer:

Yes, it depends on how much time he needs. 1.5/4 to run to the lake. 1.5/4 to run back. Not stopping, no cheating. haha

cluponka [151]3 years ago

4 0

Answer:yes

Step-by-step explanation:

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Two congruent angles have the same angle measure.

muminat

Answer:

True is the ans.

I hope it helps you.

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2 years ago

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Solve the simultaneous equations 4x+8y=-4 2y-5x=23

ad-work [718]

Answer:

x = -4, y = 3/2

Step-by-step explanation:

simplify the 1st equation by dividing each term by 4 to get:

x + 2y = -1

-5x + 2y = 23

Subtract to get: 6x = -24

x = -4

find 'y': 2y - 5(-4) = 23

2y + 20 = 23

2y = 3

y = 3/2

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2 years ago

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Generalize the pattern by finding the nth term 2, 6, 12, 20...

Nastasia [14]

32, 38, so on. So its +4 then +8 then +12 +16 +20....

8 0

2 years ago

jeka57 [31]

Answer:

<h2> 5</h2>

Step-by-step explanation:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\(-5,1)\quad\implies\quad x_1=-5\,,\ \ y_1=1\\\\(-1,4)\quad\implies\quad x_2=-1\,,\ \ y_2=4\\\\d=\sqrt{(-1+5)^2+(4-1)^2}= \sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5$

4 0

2 years ago

There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con

grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

$\square ABCD$

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$

$\angle BAC = \angle DCA$

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

$\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$

and

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$

So, the congruent sides and angles of △ABE and △CDE are:

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$ ---- S

$\angle BAC = \angle DCA$ ---- A

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$ or $\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$ --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0

2 years ago