Question

While doing an experiment a physics student recorded the following sequence of elapsed times (in seconds) in a lab notebook 2.02 24.6 2.88 2.18 2.78 2.35 2.22
the mean is approximately ( ) seconds.

Answer 1

To find the mean. You would add up all the numbers then divide by how many numbers there are.



2.02+24.6+2.88+2.18+2.78+2.35+2.22= 39.03

39.03/7=5.5757


ANSWER: 5.5757