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Volgvan
3 years ago
14

What is the answer for 5-(-8)-(-2)?​

Mathematics
1 answer:
asambeis [7]3 years ago
8 0
The answer is 15

step by step explanation:

5-(-8)-(-2)

convert the subtraction to addition

5+8+2 = 15
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Algebra 2 (picture shown)
TEA [102]

Answer:

<em>M(13)=14.3 gram</em>

Step-by-step explanation:

<u>Exponential Decay Function</u>

The exponential function is used to model natural decaying processes, where the change is proportional to the actual quantity.

An exponential decaying function is expressed as:

C(t)=C_o\cdot(1-r)^t

Where:

C(t) is the actual value of the function at time t

Co is the initial value of C at t=0

r is the decaying rate, expressed in decimal

The element has an initial mass of Mo=970 grams, the decaying rate is r=27.7% = 0.277 per minute.

The equation of the model is:

M(t)=M_o\cdot(1-r)^t

M(t)=970\cdot(1-0.277)^t

Operating:

M(t)=970\cdot 0.723^t

After t=13 minutes the remaining mass is:

M(13)=970\cdot 0.723^{13}

Calculating:

M(13)=14.3 gram

4 0
3 years ago
How do you do 8x+20z
Greeley [361]

Answer:

4(2x+5x)

Step-by-step explanation:

Factor 4 out of 8x+20z

3 0
4 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
iren2701 [21]

8x - 1 < 15 \\ 8x < 16 \\ x < 2
the answer is x<2




good luck
7 0
3 years ago
Read 2 more answers
Please help the first two answers aren’t right.
Airida [17]
It has to have an average of 10 feet per minute for 5 minutes, which means in five minutes the total of feet would have to be 50.
So you would add all these numbers up and you would get 38.
50 - 38 = 12 so the answer is 12ft
4 0
3 years ago
Maria drove to a business appointment at 50mph in the morning. Her average speed on the return trip in the afternoon was 40 mph.
MakcuM [25]

Answer:

Distance to appointment point = 5 miles

Step-by-step explanation:

Let s be the distance to the appointment point,

We have Maria drove to a business appointment at 50mph in the morning.

Time taken in the morning

               t_m=\frac{s}{50}=0.02s

Her average speed on the return trip in the afternoon was 40 mph.

Time taken in the afternoon

               t_a=\frac{s}{40}=0.025s

Given that the return trip took 1/4hr longer because of traffic.

That is

             t_a-t_m=\frac{1}{4}hr=0.025hr

Substituting

             t_a-t_m=0.025hr\\\\0.025s-0.02s=0.025\\\\s=5miles

Distance to appointment point = 5 miles

7 0
3 years ago
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