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shepuryov [24]
3 years ago
10

Problem solving: Janine is 7 years younger than Lucy and 4 years older than

Mathematics
1 answer:
Zinaida [17]3 years ago
3 0

Answer:

Janine=12.6(repeating) Samantha=15.6(repeating) Lucy=19.6(repeating)

Step-by-step explanation:

Lets concentrate on one person, Janine.

<em>Janine = Lucy - 7</em>

<em>Janine = Samantha - 3</em>

If the averae of the 3 people's ages is 16, then we should multiple that by three to get 48, the number of their ages combined.

<em>Janine + Lucy + Samantha = 48</em>

The differences between Janine to Lucy and Janine to Samantha combined is 10, so we can subtract that from 48 to get 38, which is 3 times Janines age.

<em>38/3=12.6(repeating)</em>

That is Janine's age. We can use that to find both Lucy's and Samantha's ages respectively by using their equations. Lucy's is 19.6(repeating) and Samantha's is 15.6(repeating). I hope you can give me brainliest, and that this helped!

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