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3 years ago

-4(-v-2u+4)what is the answer

Mathematics

2 answers:

emmasim [6.3K]3 years ago

7 0

-4(-v-2u+4) = 4v + 2u - 16

Paha777 [63]3 years ago

5 0

4v+8u-16 there you go

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Is terry swim three lapse in 2.5 minutes how long would it take her to swim 20 laps at the same rate

beks73 [17]

3 laps in 2.5 minutes

1 lap = 2.5/3 minute

20 laps = (2.5/3)*20 = 16.67

20 laps ≈ 16.67 minutes

5 0

4 years ago

Rewrite with only sin x and cos x.

Annette [7]

Option A

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

$cos 3x = cos(x + 2x)$

We know that,

$\cos (a+b)=\cos a \cos b-\sin a \sin b$

Therefore,

$\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x$ ---- eqn 1

We know that,

$\sin 2 x=2 \sin x \cos x$

$\cos 2 x=\cos ^{2} x-\sin ^{2} x$

Substituting these values in eqn 1

$\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)$ -------- eqn 2

We know that,

$\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x$

Applying this in above eqn 2, we get

$\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)$

$\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}$

$\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x$

Therefore,

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Option A is correct

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3 years ago

How to write 9 thousands 3 hundreds 4 ones

Nataly [62]

the answer is 9304=9 thousands 3 hundreds 4 ones

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Cerrena [4.2K]

Answer:

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Step-by-step explanation:

$\sqrt{(4-4)^{2}+(5+3)^{2} } \\\\\\\sqrt{8^{2} } \\\\8$

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