If angle 4 equals 50 degrees find the measure of angle 5 will mark brainiest
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Using the law of sines, it is found that 1 triangle can be formed with the given conditions.
<h3>What is the law of sines?</h3>Suppose we have a triangle in which:
- The length of the side opposite to angle A is a.
- The length of the side opposite to angle B is b.
- The length of the side opposite to angle C is c.
The lengths and the sine of the angles are related as follows:
Hence, for this problem, we have that the relation is:
G = 54º
A triangle can have one angle of 64º and another of 54º, hence 1 triangle can be formed with the given conditions.
More can be learned about the law of sines at brainly.com/question/25535771
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Answer: It's a tie between f(x) and h(x). Both have the same max of y = 3
The highest point shown on the graph of f(x) is at (x,y) = (pi,3). The y value here is y = 3.
For h(x), the max occurs when cosine is at its largest: when cos(x) = 1.
So,
h(x) = 2*cos(x)+1
turns into
h(x) = 2*1+1
h(x) = 2+1
h(x) = 3
showing that h(x) maxes out at y = 3 as well
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Note: g(x) has all of its y values smaller than 0, so there's no way it can have a max y value larger than y = 3. See the attached image to see what this graph would look like if you plotted the 7 points. A parabola seems to form. Note how point D = (-3, -2) is the highest point for g(x). So the max for g(x) is y = -2
The highest point shown on the graph of f(x) is at (x,y) = (pi,3). The y value here is y = 3.
For h(x), the max occurs when cosine is at its largest: when cos(x) = 1.
So,
h(x) = 2*cos(x)+1
turns into
h(x) = 2*1+1
h(x) = 2+1
h(x) = 3
showing that h(x) maxes out at y = 3 as well
--------------------------------
Note: g(x) has all of its y values smaller than 0, so there's no way it can have a max y value larger than y = 3. See the attached image to see what this graph would look like if you plotted the 7 points. A parabola seems to form. Note how point D = (-3, -2) is the highest point for g(x). So the max for g(x) is y = -2
We can start to solve this problem by using what we know. The recipe calls for 2/3 cup of flour per 1/4 batch of cookies. Now, If we want to write the rate as a complex fraction, we can replace the per with a division sign. This makes it become (2/3)/(1/4) or
