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butalik [34]
3 years ago
14

If the hypothesis is false, an argument cannot be valid, how would you explain this?

Mathematics
1 answer:
Elodia [21]3 years ago
8 0
If the hypothesis was wrong, all you simply have to do is state the hypothesis was wrong and why you think it was, and add what you can do to change it or to make it better so next time it will be right. Just state what you did and how you got your answer.

I hope that helps!
You might be interested in
What number has the same value as 14 tens
tangare [24]
If there are 14 tens, that is 14 multiplied by 10. 14 x 10 = 140.

140 is the answer.

Hope this helps :)
8 0
3 years ago
How do I change z= -14+ 8i from rectangular form to polar form?
Olenka [21]
The answer will be z=-6 because 16-8=6
3 0
3 years ago
Help !! Pleaseeeeeeeee
marysya [2.9K]

Answer:

Step-by-step explanation:

arc BE is the same as the interior angle, or 76°

BE = 76 °

we can also find arc CE the same way,  b/c we can see that the interior angle is the suppment with 76  or   180-76 = CE  or 104°

Now we know all the arcs but arc CD

so use the idea that all the way around the circle is 360°

360 = 76 + 104 + 140 + CD

360 - 76 - 104 - 140 = CD

40 = CD

CD = 40 °

7 0
3 years ago
The circumference of a circle can be found using the formula C = 2r. Which is an equivalent equation solved for r? r = C r = C(2
vaieri [72.5K]

Answer:

r equals StartFraction C Over 2 pi EndFraction

Step-by-step explanation:

we know that

The circumference of a circle is equal to

C=2\pi r

where

r is the radius of the circle

Solve for r

That means -----> isolate the variable r

Divide by 2π both sides

\frac{C}{2\pi}=\frac{2\pi r}{2\pi}

Simplify right side

\frac{C}{2\pi}=r

Rewrite

r=\frac{C}{2\pi}

so

r equals StartFraction C Over 2 pi EndFraction

5 0
3 years ago
Read 2 more answers
Circle O, with center (x, y) passes through the points A(0, 0), B(-3, 0), and C(1, 2). Find the coordinates of the center of the
KonstantinChe [14]

Answer:

The center of the circle is

(-\frac{3}{2},2)

Step-by-step explanation:

Let the equation of the circle be

x^2+y^2+2ax+2by+c=0, where (-a,-b) is the center of this circle.

The points lying the circle must satisfy the equation of this circle.

A(0,0)

We substitute this point to get;

0^2+0^2+2a(0)+2b(0)+c=0

\implies c=0

B(-3,0)

(-3)^2+0^2+2a(-3)+2b(0)+c=0

\implies 9+0-6a+0+c=0

\implies -6a+c=-9

But c=0

\implies -6a=-9

\implies a=\frac{3}{2}

C(1,2)

1^2+2^2+2a(1)+2b(2)+c=0

1+4+2a+4b+c=0

2a+4b+c=-5

Put the value of 'a' and 'c' to find 'b'

2(\frac{3}{2})+4b+0=-5

3+4b+0=-5

4b=-5-3

4b=-8

b=-2

Hence the center of the circle is

(-\frac{3}{2},2)

8 0
3 years ago
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