Equation of the perpendicular
y= 2x+6
slope of the perpendicular = 2
slope of the req. line = -1/2
equation of the req. line
y - y1 = m(x - x1)
y - 2 = -1/2(x + 4)
2(y - 2) = -1(x + 4)
2y - 4 = -x - 4
2y = -x
y = (-1/2)x
this is your req. equation of line.
The triangle classifies as a acute triangle.
Answer:
I think the IQR is 100
Step-by-step explanation:
You would have to find the first and third quartiles first. After that you would subtract the third quartile by the first to get the IQR
The answer is 31/35
Hope it helps!
Complete question is;
A 21 ft ladder is leaning against a tall wall with the foot of the ladder placed at 7 feet from the base of the wall and the angle of elevation is?
Answer:
θ = 70.5°
Step-by-step explanation:
The angle of elevation simply means the angle that the ladder makes with the ground. Let's call this angle θ.
I've attached a diagram showing the triangle made by this ladder and the wall.
From the attached diagram, we can see the triangle formed by the ladder and the wall.
We can find the angle of elevation θ from trigonometric ratios.
Thus;
7/21 = cos θ
cos θ = 0.3333
θ = cos^(-1) 0.3333
θ = 70.5°
