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Y_Kistochka [10]
3 years ago
12

The function f(x) = square root -x is shown on the graph. Which statement is correct?

Mathematics
2 answers:
Mrrafil [7]3 years ago
5 0

Domain are the x values and Range are the y values.

Answer: The domain of the graph is all real numbers less or equals to zero.

EastWind [94]3 years ago
4 0

Answer:

The Domain of the graph is all real numbers less than or equal to 0.


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Answer:

33.3%

Step-by-step explanation:

Step one:

given data

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change in population= 16000-12000= 4000

Step two:

% increase= change in population/initail population *100

%increase= 4000/12000*100

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7+5(x-3)=7(x+2) Find the solution with the work shown please.
eduard

Answer:

x=−11

Step-by-step explanation:

7+5(x−3)=7(x+2)

Step 1: Simplify both sides of the equation.

7+5(x−3)=7(x+2)

7+(5)(x)+(5)(−3)=(7)(x)+(7)(2)(Distribute)

7+5x+−15=7x+14

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5x+−8=7x+14

5x−8=7x+14

Step 2: Subtract 7x from both sides.

5x−8−7x=7x+14−7x

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Step 3: Add 8 to both sides.

−2x−8+8=14+8

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Step 4: Divide both sides by -2.

−2x

−2

=

22

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x=−11

3 0
3 years ago
Read 2 more answers
Integrate ln(x^2-x+2).
Lilit [14]
∫㏑(x² - x + 2) dx = ∫㏑(x² - 2x + x + 2) dx
∫㏑(x² - x + 2) dx = ∫㏑[x(x) - x(2) + 1(x) - 1(2)] dx
∫㏑(x² - x + 2) dx = ∫㏑[x(x - 2) + 1(x - 2)] dx
∫㏑(x² - x + 2) dx = ∫㏑[(x + 1)(x - 2)] dx
∫㏑(x² - x + 2) dx = ∫㏑(x + 1) + ㏑(x - 2) dx
∫㏑(x² - x + 2) dx = ∫㏑(x + 1) dx + ∫㏑(x - 2) dx
∫㏑(x² - x + 2) dx = [x㏑(x + 1) - (x - ㏑(|x + 1|)) + C] + [x㏑(x - 2) - (x + ㏑(|x - 2|)) + C]
∫㏑(x² - x + 2) dx = [x ln(x + 1) + x㏑(x - 2)] + [(-x +㏑(|x + 1|)) + (-x - ln(|x - 2))] + {C + C}
∫㏑(x² - x + 2) dx = x㏑(x² - x + 2) + [-2x - (㏑(|x + 1|))/㏑(|x - 2|))] + 2C
∫㏑(x² - x + 2) dx = x㏑(x² - x + 2) - 2x - (㏑(|x + 1|))/㏑(|x - 2|)) + 2C
4 0
3 years ago
What is the surface area of the rectangle prism below? HELP ME ASAP PLEASE !!
zaharov [31]

Answer:

C. 248

Step-by-step explanation:

A=2(wl+hl+hw)\\2(4*6+10*6+10*4)\\2(24+60+40)\\48+120+80=248

4 0
3 years ago
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